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3 years ago

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bills normal temperature is 98.6 today ballistic and has a temperature of 104.3 how many degrees above his normal temperature is

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1 answer:

kkurt [141]3 years ago

4 0

Answer:

Today's temperature is 5.7 degrees above Bill's normal temperature.

Step-by-step explanation:

Given

Represent the normal temperature with N and today's temperature with T.

Such that:

$N = 98.6$

$T = 104.3$

Required

Determine the temperature above the normal temperature

The interpretation of this is to calculate the difference between Bill's normal temperature and Bill's today temperature.

Represent the difference with D

D is calculated as follows:

$D = T - N$

Substitute values for T and N

$D = 104.3 - 98.6$

$D = 5.7$

Hence, today's temperature is 5.7 degrees above Bill's normal temperature.

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Kay [80]

Answer:

$\frac{p^2 - 16} {4p^2 + 16}$

Step-by-step explanation:

I will work with radians.

$\frac {\cos^2 \left(\frac{\pi}{2}-x \right)+\sin(-x)-\sin^2 \left(\frac{\pi}{2}-x \right)+\cos \left(\frac{\pi}{2}-x \right)} {[\sin(\pi -x)+\cos(-x)] \cdot [\sin(2\pi +x)\cos(2\pi-x)]}$

First, I will deal with the numerator

$\cos^2 \left(\frac{\pi}{2}-x \right)+\sin(-x)-\sin^2 \left(\frac{\pi}{2}-x \right)+\cos \left(\frac{\pi}{2}-x \right)$

Consider the following trigonometric identities:

$\boxed{\cos\left(\frac{\pi}{2}-x \right)=\sin(x)}$

$\boxed{\sin\left(\frac{\pi}{2}-x \right)=\cos(x)}$

$\boxed{\sin(-x)=-\sin(x)}$

$\boxed{\cos(-x)=\cos(x)}$

Therefore, the numerator will be

$\sin^2(x)-\sin(x)-\cos^2(x)+\sin(x) \implies \sin^2(x)- \cos^2(x)$

Once

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$\cos(x)=4$

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Now let's deal with the numerator

$[\sin(\pi -x)+\cos(-x)] \cdot [\sin(2\pi +x)\cos(2\pi-x)]$

Using the sum and difference identities:

$\boxed{\sin(a \pm b)=\sin(a) \cos(b) \pm \cos(a)\sin(b)}$

$\boxed{\cos(a \pm b)=\cos(a) \cos(b) \mp \sin(a)\sin(b)}$

$\sin(\pi -x) = \sin(x)$

$\sin(2\pi +x)=\sin(x)$

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$[\sin(\pi -x)+\cos(-x)] \cdot [\sin(2\pi +x)\cos(2\pi-x)] \implies [\sin(x)+\cos(x)] \cdot [\sin(x)\cos(x)]$

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The final expression will be

$\frac{p^2 - 16} {4p^2 + 16}$

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Answer:

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Step-by-step explanation:

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