Somebody help me with this please .
1 answer:
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Answer:
Leg of an isosceles right triangle is 7.99 long.
Step-by-step explanation:
Given:
Length of the hypotenuse =11.31
To find:
Length of the leg of an isosceles right triangle =?
Solution:
According to Pythagorean's Theorem, we have
-----------------------------(1)
Here were are given as isosceles triangle, so the two sides will be of same length
So equation 1 can be rewritten as
Substituting the value of hypotenuse
a = 7.99
Rise over run, -2/4 or -1/2 so the slope is -1/2 or -0.5. (View picture) And the slope is negative because you are going down wards \ and the "rise" is going down.
The equation of the tangent line at x=1 can be written in point-slope form as
... L(x) = f'(1)(x -1) +f(1)
The derivative is ...
... f'(x) = 4x^3 +4x
so the slope of the tangent line is f'(1) = 4+4 = 8.
The value of the function at x=1 is
... f(1) = 1^4 +2·1^2 = 3
So, your linearization is ...
... L(x) = 8(x -1) +3
or
... L(x) = 8x -5
