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serious [3.7K]
4 years ago
7

Is the decimal form of 13/3 a rational number.

Mathematics
2 answers:
Bogdan [553]4 years ago
8 0

Answer with explanation:

→A number is said to be rational number , if it can be written in the form of

\frac{p}{q}, where q≠0.

→A rational number is said to be terminating decimal if denominator of rational number is in the form of

  2^m \text{or} 5^n \text{or} 2^m \times 5^n

otherwise , it is non terminating repeating decimal.

→The given Rational number is

   \frac{13}{3}

Here denominator contains neither powers of 2 , nor powers of 5, nor power of 2 × 5, so it is a non terminating repeating decimal , still a rational number.

evablogger [386]4 years ago
6 0
Yes because its a whole number
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Step-by-step explanation:

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erma4kov [3.2K]

Answer:

<u>y ≤ 4</u>

Step-by-step explanation:

Solving :

  • Highest y-value is 4
  • The other y-values are less than 4
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5 0
2 years ago
Given f'(x)=(x-4)(6-2x) find the x-coordinate for the relative minimum of the graph f(x).
vlabodo [156]
<span>The graph you plotted is the graph of f ' (x) and NOT f(x) itself. </span>

Draw a number line. On the number line plot x = 3 and x = 4. These values make f ' (x) equal to zero. Pick a value to the left of x = 3, say x = 0. Plug in x = 0 into the derivative function to get

f ' (x) = (x-4)(6-2x)
f ' (0) = (0-4)(6-2*0)
f ' (0) = -24

So the function is decreasing on the interval to the left of x = 3. Now plug in a value between 3 and 4, say x = 3.5

<span>f ' (x) = (x-4)(6-2x)
</span><span>f ' (3.5) = (3.5-4)(6-2*3.5)
</span>f ' (3.5) = 0.5

The function is increasing on the interval 3 < x < 4. The junction where it changes from decreasing to increasing is at x = 3. This is where the min happens.

So the final answer is C) 3
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3 years ago
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Vikentia [17]

Answer: <em>3w+4b</em>

Step-by-step explanation:

<em>Take your given equation</em>

<em>w+w+w+b+b+b+b</em>

<em>There are 3 w's and 4 b's</em>

<em>Combine like terms</em>

<em>w+w+w=</em><em>3w</em>

<em>b+b+b+b=</em><em>4b</em>

<em>3w+4b</em>

3 0
3 years ago
Read 2 more answers
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