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k0ka [10]
3 years ago
14

How do you solve -3 + 5 +6g =11 - 3g?

Mathematics
2 answers:
expeople1 [14]3 years ago
8 0
Add -3 +5 u get 2
the add 3g to 6g to get 9g
then u have 2+9g=11
subtract 2 to both sides u get 9g=9
divide 9 u get 1=g hope I helped
MariettaO [177]3 years ago
5 0

Final Answer: g = 1

Steps/Reasons/Explanation:

Question: How do you solve -3 + 5 +6g = 11 - 3g?

<u>Step 1</u>: Simplify -3 + 5 + 6g to 6g + 2.

6g + 2 = 11 - 3g

<u>Step 2</u>: Subtract 2 from both sides.

6g = 11 - 3g - 2

<u>Step 3</u>: Simplify 11 - 3g - 2 to -3g + 9.

6g = -3g + 9

<u>Step 4</u>: Add 3g to both sides.

6g + 3g = 9

<u>Step 5</u>: Simplify 6g + 3g to 9g.

9g = 9

<u>Step 6</u>: Divide both sides by 9.

g = 1

~I hope I helped you :)~

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<u>Step-by-step explanation:</u>

Here we have , If I have a line that starts at the origin (0,0), and goes 13 meters at an angle of π/6 in the standard position (i.e. 30° north of east) . We need yo find how far does it go in the y direction (north), and how far does it go in the x direction (east). Let's find out:

According to question we have a right angle triangle as :

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We know that ,

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⇒ \frac{\sqrt{3} }{2} = \frac{Base}{13}

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We know that ,

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