Question

Find the equation of the line with gradient 3/4 which passes through point (1,1)

Answer 1

Let the equation of the line be: y = mx + c
Since m is the gradient, m = 3/4
∴ y = $\frac{3}{4}$ + c
c is the y-intercept, and to find it, substitute the coordinate (1, 1) into the equation:
1 = $\frac{3}{4}$ × 1 + c
c = 1 - $\frac{3}{4}$
c = $\frac{1}{4}$
∴ y = $\frac{3}{4}$x + $\frac{1}{4}$

I hope the calculations are correct...