<span>"In order to get the Least Common Multiple of 50 and 20 we need to factor each value and then we need to choose all of the factors which appear in any column and then multiply them."
50: 2 55
20: 225
LCM: 2255
</span><span>The (LCM) is: 2 x 2 x 5 x 5 = 100
</span>
<span>"To find the Greates Common Factor (GCF) of 20 and 50 we need to factor each value first and then choose all the copies of factors and then multiply them."
</span>
<span>20: 255
</span>
50: 55
The GCF is: 2 and 5 so you need to multiply and then you will get The Greates Common Factor. The greates common factor is: 2 x 5 = 10
Answer:
The distance between the points is 5 units
Step-by-step explanation:
I used distance formula for the question using two points
I
We have the following limit:
(8n2 + 5n + 2) / (3 + 2n)
Evaluating for n = inf we have:
(8 (inf) 2 + 5 (inf) + 2) / (3 + 2 (inf))
(inf) / (inf)
We observe that we have an indetermination, which we must resolve.
Applying L'hopital we have:
(8n2 + 5n + 2) '/ (3 + 2n)'
(16n + 5) / (2)
Evaluating again for n = inf:
(16 (inf) + 5) / (2) = inf
Therefore, the limit tends to infinity.
Answer:
d.limit does not exist
First of all, assuming that the "ground level" is 0;
The lift is not starting from 0, so we also need to account for the extra 15 meters above the ground the lift is.
The total distance the lift would cover in the downward direction: 15+350=365m
Now, you know that the lift covers 5 m/min
Therefore, 5x=365 (ignoring units because they can complicate things)
x=365/5
x=73 minutes
Therefore, they would take 73 minutes to reach 350 m deep into the ground with a starting position 15 m above the ground.
Hope I helped :)
Setup 2 problems
2x - 7 < 15 and 2x - 7 > -15
2x < 22 2x > -8
x < 11 x > -4
Or you can write it -4 < x < 11
