Y2-Y1
Over X2-X1 and then there is your slode
Y = 9x - 5...the slope here is 9...a parallel line will have the same slope.
y = mx + b
slope(m) = 9
(5,-4)...x = 5 and y = -4
now we sub and solve for b, the y int
-4 = 9(5) + b
-4 = 45 + b
-4 - 45 = b
-49 = b
so ur parallel line is : y = 9x - 49
y = 9x - 5...slope is 9. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So the slope we need is -1/9.
y = mx + b
slope(m) = -1/9
(5,-4)...x = 5 and y = -4
now we sub and solve for b, the y int
-4 = -1/9(5) + b
-4 = -5/9 + b
-4 + 5/9 = b
-36/9 + 5/9 = b
- 31/9 = b
so ur perpendicular line is : y = -1/9x - 31/9
Chuy planned on saving $55 a week at the rate hes going he would of saved up in less then 25 weeks he would of needed to save atleast $50 per week to meet his goal
