3 years ago

What is an equation of a line in point slope form that passes through (-2, -6) and has a slope of 1/3

Mathematics

1 answer:

Hitman42 [59]3 years ago

7 0

Answer:

y + 6 = (1/3)(x + 2)

Step-by-step explanation:

The point-slope form of the equation of a line with slope m through point (h, k) is ...

... y - k = m(x - h)

Fill in the numbers you are given for slope and point.

... y -(-6) = (1/3)(x -(-2))

Simplify the double negatives:

... y + 6 = (1/3)(x + 2)

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D= V(x2 - 1)2 + (12 - y1)?

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Answer:

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Step-by-step explanation:

Given figure is the graph having E and F coordinate

The coordinate of point E = ( $x_1$ , $y_1$ ) = ( - 2 , -4 )

The coordinate of point F = ( $x_2$ , $y_2$ ) = ( 2 , 2 )

Let The distance between the points E and F = D

So, D = $\sqrt{(x_2 - x_1)^{2} + ( y_2 - y_1 )^{2} }$

or, D = $\sqrt{(2 - (- 2 ))^{2} + ( 2 - ( - 4 ))^{2} }$

Or, D = $\sqrt{( 4 )^{2} + ( 6 )^{2} }$

or, D = $\sqrt{16 + 36}$

∴ D = $\sqrt{52}$

I.e D = 7.21 unit

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