Question

Write an equation of the circle with center 6.-9) and radius 10!

Answer 1

The equation of the given circle is $(x-6)^{2}+(y+9)^{2}=100.$

Step-by-step explanation:

Step 1:

The equation of a circle with its center at (h, k) and a radius of r is given by

$(x-h)^{2}+(y-k)^{2}=r^{2}.$

The h value is the x coordinate and the k value is the y coordinates, so (h, k) is (6, -9).

The radius is given as 10 so $r =10$ and $r^{2} = 100.$

Step 2:

By substituting the values we know, we get

$(x-h)^{2}+(y-k)^{2}=r^{2} = (x-6)^{2}+(y-(-9))^{2}=10^{2}.$

So the equation of the given circle is

$(x-6)^{2}+(y+9)^{2}=100.$