Arithmetic sequence: must have a constant common difference.
3/20-1/10=(3-2)/20=1/20
5/30-3/20=(10-9)/60=1/60
Difference is not constant, so no.
Geometric sequence: must have a common ratio
30/20 / (1/10) = 15
5/30 / (3/20) = 100/90 = 10/9
ratio is not constant, so no.
The answer is (c) neither geometric nor arithmetic
Answer: 6x+18
Step-by-step explanation: Because of the Distributive property, you would multiply the 6 by the’x’ and 3, as they are in the parenthesis.
Answer:
52%
Step-by-step explanation:
52 out of 100 is the same as .52, when you put that as a percentage, you get 52%
Company one cause the equation for it is y=0.04x. If you do y=0.04(500) u get 20$ as the total.
Answer:
→<u> </u><u>First</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>1</u>
→<u> </u><u>Second</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>2</u>
→<u> </u><u>Third</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>5</u>
Step-by-step explanation:
• let numbers be x, y and z

• from eqn 2, make x the subject:

• substitute all variables in eqn 3:

• find z

• find x:

Rounding to nearest value:
