Can someone help? I really need it

Mathematics

1 answer:

chubhunter [2.5K]2 years ago

3 0

Answer:

Step-by-step explanation:

In direct proportion, as the first variable increases (decreases), the second variable also increases (decreases). In mathematical statements, it can be expressed as y = kx. This reads as “y varies directly as x” or “y is directly proportional as x” where k is constant in the equation

In this equation, y and x are the two directly proportional quantities and k is a proportionality constant that tells you exactly how they are related (like 10 cents/piece above). On a graph, a direct proportion will look like a straight line and the slope of the line will be equal to the constant k

You might be interested in

What is the volume of this container

ValentinkaMS [17]

the volume of the container will be 480

8 0

2 years ago

Read 2 more answers

Why the derivative of (x^2/a^2) = (2x/a^2)?

Neko [114]

I assume you're referring to a function,

$f(x) = \dfrac{x^2}{a^2}$

where <em>a</em> is some unknown constant. By definition of the derivative,

$\displaystyle f'(x) = \lim_{h\to0}{f(x+h)-f(x)}h$

Then

$\displaystyle f'(x) = \lim_{h\to0}{\frac{(x+h)^2}{a^2}-\frac{x^2}{a^2}}h \\\\ f'(x) = \frac1{a^2} \lim_{h\to0}{(x+h)^2-x^2}h \\\\ f'(x) = \frac1{a^2} \lim_{h\to0}{(x^2+2xh+h^2)-x^2}h \\\\ f'(x) = \frac1{a^2} \lim_{h\to0}{2xh+h^2}h \\\\ f'(x) = \frac1{a^2} \lim_{h\to0}(2x+h) = \boxed{\frac{2x}{a^2}}$