The product of x and the sum of 6 and 8 times the square of x
2 answers:
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Answer:
x-5+
Step-by-step explanation:
If x+2 is a factor, -2 is a zero. So we can put -2 in the left-hand corner of your synthetic division, bring the coefficients down so you'll have a set up like this:
-2 | 1 -3 -7
____________
1. bring down the 1:
-2 | 1 -3 -7
____________
1
2. multiply that by -2 and enter the result underneath 3:
-2 | 1 -3 -7
-2
___________
1
a. then, add through:
-2 | 1 -3 -7
-2
___________
1 -5
3. Do the same for -5 (multiply by the zero -2), enter that underneath -7 and add through:
-2 | 1 -3 -7
-2 10
___________
1 -5 3
Now, reassign the coefficients to their x. Because we already factored out an x with the zero, the 1 is assigned to 'x' rather than back to ''. The '-5' will not have an x attached. '3' is your remainder and cannot be divided out any further, so it will be written as
. Finally, just put them back together to get x-5+
.
Hope this helped!