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Bas_tet [7]
3 years ago
12

The product of x and the sum of 6 and 8 times the square of x

Mathematics
2 answers:
Kamila [148]3 years ago
8 0

Let's separate this problem into several parts:

1. The product of x

AND

2. The sum of 6 and 8

TIMES

3. The square of x

So translating this word problem into numbers, we have:

x TIMES (6+8) TIMES x²

so that is:

x * 14 * x²

which is:

14x^(2+1) = 14x³

ololo11 [35]3 years ago
3 0

Answer:

x(6 + 8x)

Step-by-step explanation:

Symbolically, that would be x(6 + 8x).  You could expand this to 6x + 8x^2.

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alukav5142 [94]

Answer:

61

Step-by-step explanation:

(x2-x1)2 + (y2-y1)2

(5-0)2 + (-3-3)2

25+36= 61

square root of 61

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3 years ago
How many sequences of length 5 can be made when each component of the sequence can take 3 different values?
kozerog [31]
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3^5=243
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3 years ago
1. If the domain of a function f(x) is the set {10, 20, 30}. What does the information tell you about f-1(x)?
ziro4ka [17]

PART A (1 in diagram)

Each mapping diagram represents a function because none of the elements in the inputs maps on to two different elements in the outputs.

1. The domain of the given function f(x) is the set {10, 20, 30}.

All we can say about

{f}^{ - 1} (x)

is that, it has a range of {10, 20, 30}.

This is because the domain of a function becomes the range of its inverse function.

2. If the graph of a function f(x) includes the point (3, 0), then the graph of the inverse function ,

{f}^{ - 1} (x)

will contain the point (0,3).

Reason:The point on the graph of the inverse function is obtained by reflecting the corresponding point on the graph of the function in the line y=x. We just have to swap the coordinates.

In simple terms the domain of the function becomes the range of the inverse function and vice versa.

3. If the first term in an arithmetic sequence is 2.

Then we have a=2.

If the twelfth term is 211, then

a + 11d = 211...(1)

Put a=2 into this equation.

2 + 11d = 211

Solve for d.

11d = 211 - 2

11d = 209

d =  \frac{209}{11}  = 19

If

a_n = 135

then

a + (n - 1)d = 135

Substitute a=2 and d=19

2 + (n - 1)19 = 135

19(n - 1) = 133

(n - 1) =  \frac{133}{19}

n - 1 = 7

n = 7 + 1 = 8

Therefore n=8

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3 years ago
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Step-by-step explanation:

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kirill [66]

Answer:

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9=b

Step-by-step explanation:

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