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Bas_tet [7]
3 years ago
12

The product of x and the sum of 6 and 8 times the square of x

Mathematics
2 answers:
Kamila [148]3 years ago
8 0

Let's separate this problem into several parts:

1. The product of x

AND

2. The sum of 6 and 8

TIMES

3. The square of x

So translating this word problem into numbers, we have:

x TIMES (6+8) TIMES x²

so that is:

x * 14 * x²

which is:

14x^(2+1) = 14x³

ololo11 [35]3 years ago
3 0

Answer:

x(6 + 8x)

Step-by-step explanation:

Symbolically, that would be x(6 + 8x).  You could expand this to 6x + 8x^2.

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Is 5/8 greater than 6/16
aleksklad [387]
Yes , pic will explain .

7 0
3 years ago
A sixth grader weighs 90 pounds, which is 120% of what he weighed in fourth grade. How much did he weigh in fourth grade?
attashe74 [19]
 
<span>90x100=9000/120= 75 So he weighed 75lbs  
hope this helps :)</span>
5 0
3 years ago
What is the area of the triangle below? Please explain too.
Neko [114]

Answer:

144 ft^2

Step-by-step explanation:

property of 45-45-90 triangle: side lengths are 12rt2

12rt2*12rt2/2=144

5 0
3 years ago
I’m confused on this one
Mandarinka [93]

Remark

If the lines are parallel then triangle RQS will be similar to triangle RTP


From that, all three lines in one triangle will bear the same ratio to all three lines of the second triangle.


Givens

PQ = 8

QR = 5

RS = 15

ST = x + 3


Ratio

QR/RP = RS/RT


Sub and solve

RP = 5 + 8

RP = 13


RT = 15 + x + 3

RT = 18 + x


5/13 = 15 / (18 + x) Cross multiply

5(18 + x) = 195 Remove the brackets on the left.

90 + 5x = 195 Subtract 90 from both sides.

5x = 105 Divide by 5

x = 105/5

x = 21 Answer <<<<<<<

3 0
3 years ago
A 9,000-lb load is suspended from the roof in a shopping mall with a 16-ft-long solid aluminum rod. The modulus of elasticity of
Westkost [7]

Answer:

Step-by-step explanation:

Given:

elongation, x = 0.50 in

Force, f = 9000 lb

Young modulus, E = 10,000,000 psi

Maximum Stress, Sm = 30000 psi

Length, L = 16 ft

Converting ft to in,

12 in = 1 ft

=16 × 12 = 192 in

Young modulus, E = stress/strain

Stress = force/area, A

Strain = elongation, x/Length, L

E = f × L/A × E

1 × 10^7 = stress/(0.5/16)

= 26041.7 psi

Minimum stress = 26041.7 psi

Maximum stress = 30,000 psi

Stress = force/area

Area = 9000/26041.7

= 0.3456 in^2

Stress = force/area

Area = 9000/30000

= 0.3 in^2

Using minimum area of 0.3 in^2,

A = (pi/4)(d^2)

0.3 in^2 = (pi/4)(d^2)

d = 0.618 inches

diameter, d = 0.618 inches

7 0
3 years ago
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