A car is designed to last an average of 12 years with a standard deviation of 0.8 years. What is the probability that a car will
2 answers:
Due to the common probability formula I can solve that task. Refering to the task you gave, we have all the information we need. We solve it like that: 
So the answer is the first option <span>0.621%</span>
So the answer is the first option <span>0.621%</span>
Standard Deviation = A = 0.8
Mean = 12 years
We will use normal distribution to calculate probability.
Let a Random variable Z , has A = 0.8, and M= 12 years.
Probability that a car will be able to last < 10 years= P(Z<10)
=
Pr (Z < -5/2) = 0.00621[ By using standard table]
= 0.00621 ×100
=0.621%→ Option A .
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Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60
t=1