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ziro4ka [17]
3 years ago
14

Gavin and Jim share some money in a ratio of 1:3 gavin gets £15 how much did Jim get

Mathematics
1 answer:
lozanna [386]3 years ago
8 0

Answer:

$45   (corrected answer)

Step-by-step explanation:

Given

Gavin : Jim   = 1 : 3

fraction that Gavin gets = 1 / (1+3) = 1/4

fraction that Jim gets = 3 / (1+3) = 3/4

given that Gavin gets $15,

Gavin's share = (1/4) ----> equivalent to $15

Jim's share = (3/4) ----> equivalent to $15 x 3 = $45

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valentina_108 [34]
I’m not sure abt 21 but 22 is the second one and the 4th one. So 2,4.
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3 years ago
Do anybody know geometry?
choli [55]

Answer:

D. 29

Step-by-step explanation:

180 - 151 = 29

6 0
3 years ago
Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective
soldier1979 [14.2K]

Answer:

a) P[C]=p^n

b) P[M]=p^{8n}(9-8p^n)

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

P[C]=p^n

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)

c)

P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

6 0
4 years ago
TO TRANSMIT INFORMATION ON THE INTERNET, LARGE FILES ARE BROKEN INTO PACKETS OF SMALLER SIZES. EACH PACKET HAS 1,500 BYTES OF IN
stich3 [128]

Answer:

<u>A.</u> <u>It would be needed 20 packets to transmit 30,000 bytes of information and B. 45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the question:

Size of each packet of information = 1,500 bytes

Number of packets = P

Number of bytes of information = B

2. Let's answer the questions:

A. How many packets would be needed to transmit 30,000 bytes of information?

P = 30,000 ÷ 1,500

P = 20

<u>It would be needed 20 packets to transmit 30,000 bytes of information</u>

B. How much information could be transmitted in 30,000 packets?

B = 30,000 * 1,500

B = 45'000,000

<u>45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.</u>

Note: Same answer provided to question 14037480, answered by me.

7 0
3 years ago
Which choice is equivalent to the quotient shown here when x&gt;=0 square root of 35x^5 divided by the square root of 7x^3
natita [175]

Answer:

x√5 = x square root 5

Step-by-step explanation:

√35x^5 ÷ √7x^3 = √(35x^5 / 7x^3)

√(35x^5 / 7x^3) = √(5x^5 / x^3)

√(5x^5 / x^3) = √5x^(5-3) = √5x²

√5x² = x√5

3 0
3 years ago
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