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dezoksy [38]
2 years ago
10

Ahmed owns a land of breadth (x+7) units &having an area of 2+ 14x + 49 sq. Units. (i)Find its length.

Mathematics
1 answer:
elena-14-01-66 [18.8K]2 years ago
5 0

Answer:

l = (x+7) units

Step-by-step explanation:

Given that,

Breadth of the rectangle, b = (x+7) units

Area of the rectangle, A=x^2+14x+49

The area of a rectangle is given by :

A=lb\\\\l=\dfrac{A}{b}\\\\l=\dfrac{(x^2+14x+49)}{(x+7)}\\\\l=\dfrac{(x+7)^2}{(x+7)}\\\\l=(x+7)\ \text{units}

So, the length of the land is (x+7) units.

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Answer:

90

Step-by-step explanation:

180°-104°=76°( sum of angles A and B)

76°÷2=38°

x=38°

Bcuz it is an isosceles triangle ( a triangle with 2 equal sides). So, angle B and A are equal. thats why 76° must be divided by 2.

180°-104°=76°(angles on a straight line)

180°-76°=104° (sum of angle A and C)

104°÷2=52°

y=52°

it is also an isosceles triangle.

x+y=38+52=90°

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The sides of a square are all increased by 3 cm. The area of the new square is 64 cm'.
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Side of the original square is 5 cm.

Step-by-step explanation:

  • Step 1: Let the side of the original square be x. Then side of the new square = x + 3 and Area of new square = 64 cm²

Area of a square = (side)²

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⇒ 64 = x² + 6x + 9

⇒ x² + 6x - 55 = 0

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⇒ (x + 11)(x - 5) = 0

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Side of the original square is 5 cm.

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