The answer for this problem is 2 since it is not specified whether it is adjacent to the right or adjacent to the left.
If it is adjacent to the right, the answer is:
p (k) = 2 * p(1) + 2 * k
If the is adjacent to the left, the answer is:
P (k) = 2 *p(1) +2 * (k-2)
Set x as adult tickets.
Set y as children's tickets.
x + y = 15
30x + 20y = 270
Solve for x in the first equation.
x + y = 15
x = 15 - y
Plug this into the second equation.
30x + 20y = 270
30(15 - y) + 20y = 270
450 - 30y + 20y = 270
450 - 10y = 270
-10y = -180
y = 18
If there is 18 childrens tickets, there should be -3 adult tickets.
This is impossible, and this impossible answer occured because the question is written wrong.
There are a total of 15 tickets
The smallest costing ticket is the childrens ticket, which costs 20$.
If he only bought children tickets, this would be 20x15 which is 300$.
300$ is over 270$, which makes the question impossible.
Answer:
15/2
Step-by-step explanation:
5 3/4 - 1/6x = 4 1/2
move the variable to it's own side.
5 3/4 - 4 1/2 = 1/6x
change the subtracting side to have common denominators
5 3/4 - 4 2/4 = 1/6x
1 1/4 = 1/6 x
divide both sides by 1/6, same thing as multiplying both sides by 6 (reciprocal)
30/4 = x
reduce: 15/2 = x
I think the answer would be 4 and the reason why is because