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Bingel [31]
3 years ago
8

Dida bought a scratch ticket for $2.00. The potential payoffs and probability of those payoffs are shown below.

Mathematics
1 answer:
kakasveta [241]3 years ago
4 0

9514 1404 393

Answer:

  (b)  $1.15

Step-by-step explanation:

The expected value is the sum of products of payoff and probability:

  $0×0.15 +0.50×0.5 +1.0×0.2 +2.0×0.1 +10×0.05

  = $0 +0.25 +0.20 +0.20 +0.50

  = $1.15 . . . . expected value of the scratch ticket

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-4(-3x - 8) - 4x + 8 = -8x + 40
Andrew [12]
First we expand and combine the terms on the left side.  This gives us

12x + 32 -4x + 8 = -8x + 40 

8x + 40 = -8x + 40.  Because the two sides cancel each other out when you try and bring all the x to one side, the answer is x = 0.
3 0
3 years ago
A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet
Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

L_{1} = 2W_{1}

Also, the area of the walkway of 2 feet wide is 448:

W_{2} = 2 ft

A_{T} = W_{2}*L_{2} = 448 ft^{2}

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

A_{T} = A_{1} + A_{w}    (1)          

The area of the pool is given by:

A_{1} = L_{1}*W_{1}        

A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}  (2)          

And the area of the walkway is:

A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}    (3)          

Where the length of the bigger rectangle is related to the lower rectangle as follows:                  

L_{2} = 4 + L_{1} = 4 + 2W_{1}   (4)        

By entering equations (4), (3), and (2) into equation (1) we have:

A_{T} = A_{1} + A_{w}

A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}                

448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}            

224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}

224 = W_{1}^{2} + 8 + 6W_{1}

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

L_{1} = 2W_{1} = 2*12 ft = 24 ft

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!                                                                                          

8 0
3 years ago
HELP ASAP!!!!! PLEASE
german

Answer: imma say A

Step-by-step explanation: sorry if wrong

8 0
3 years ago
In Cos A = 0.4 Find The Value Of Cos 3 A.<br><br><br><br>Thenku ☃️<img src="https://tex.z-dn.net/?f=%20%5C%3A%20%5C%3A%20" id="T
s2008m [1.1K]
Answer:
- 0.944

Step-by-step explanation:
We know that,
cos 3A = 4 cos³A - 3 cos A (formula)

So,
If cos A = 0.4,

cos 3A = 4 cos³A - 3 cos A
cos 3A = 4 × (0.4)³ - 3 × (0.4)
cos 3A = 4 × 0.064 - 1.2
cos 3A = - 0.944


Hope it helps ⚜




3 0
3 years ago
Read 2 more answers
3y+3 (1-y)-y=-6PLEASE help
Murrr4er [49]
3y+4+3y-y=-6
6y-y+4=-6
5y+4=-6
5y=-10
y=-2
If you have any questions let me know
7 0
3 years ago
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