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2 years ago

Dida bought a scratch ticket for $2.00. The potential payoffs and probability of those payoffs are shown below.

Mathematics

1 answer:

kakasveta [241]2 years ago

4 0

9514 1404 393

Answer:

(b) $1.15

Step-by-step explanation:

The expected value is the sum of products of payoff and probability:

$0×0.15 +0.50×0.5 +1.0×0.2 +2.0×0.1 +10×0.05

= $0 +0.25 +0.20 +0.20 +0.50

= $1.15 . . . . expected value of the scratch ticket

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26° Х Х X = degrees Enter<br>please help asap

Alinara [238K]

Answer:

77 degrees

Step-by-step explanation:

we know all 3 points must equal 180 degrees. take 180 and subtract the known 26. since the last two points are equal divide by 2 and get 77

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What is the GCF of and 55 and 80 *

Zarrin [17]

The Greatest Common Factor of 55 and 80 is 5.

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3 years ago

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Rudik [331]

Answer:

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Step-by-step explanation:

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2 years ago

triangle abc has vertices at a(-2 3),B(0,3),c(-1,-1). Find the coordinates of the image after a reflection over the x-axis.

Crazy boy [7]

The new coordinates of the triangle after reflection from x-axis would be A(-2, -3) , B(0, -3) and C( -1, 1 )

<u>Explanation:</u>

The vertices of the triangle are A(-2 3), B(0,3), C(-1,-1)

The reflection is over the x-axis.

When the reflection is along the x-axis, the coordinates of x does not change. However, the coordinates of y does change.

The negative value of y becomes positive and the positive value of y becomes negative.

Similarly,

A(-2, 3) would become A(-2, -3)

B(0, 3) would become B(0, -3)

C(-1, -1) would become C( -1, 1 )

Therefore, the new coordinates of the triangle after reflection from x-axis would be A(-2, -3) , B(0, -3) and C( -1, 1 )

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3 years ago

Please help!! What Find the Error and explain why it is wrong!

Nata [24]

Answer:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. The real numerator in Step E should be:

$3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x$

Hence, Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

And further steps are described below:

Step D

$x^{2}-x+4 = 0$