1. your leading coefficient has to be 1 (nothing before the x^2). If there is you have to divide that out before you start.
2. Move your constant (the number without any x attached) to the other side of the equation
3. take 1/2 of the b term (the one with the x attached) and then square it and then add it to both sides
4. Factor the left side
5. Set each factor equal to 0 and solve
Here is an example:
4x^2-24x+20=0
The first term is not a 1 so we have to divide it out by 4 first
x^2-6x+5=0
Move the 5 to the other side. It becomes negative.
x^2-6x=-5
Take 1/2 of 6 (3) then square it (9) and add it to both sides.
x^2-6x+9=-5+9
Factor the left side
(x-3)(x-3)=4
(x-3)^2=4
To solve you need to square root both sides
x-3=+/-
x-3=+/-2
x=3+2=5
x=3-2=1
Those would be your two answers.
<span>Hope that helps</span>
Answer:
c is all the points in the open interval (0,25)
Step-by-step explanation:
Here given is a function
, which is continuous in the interval [0,25] and differentiable in (0,25)
Mean value theorem says there exists at least one c in the interval (0,25) such that
We have
For the given function
Hence we have c equals all the points in the open interval (0,25)
9514 1404 393
Answer:
Step-by-step explanation:
The answer statement tells you the transformation is a rotation. The original is in the 2nd quadrant, and the image is in the 1st quadrant, representing a clockwise rotation. AB points east, while A'B' points south, a rotation of 90° (clockwise). Each image point is the same distance from the origin as its preimage point. The origin is the center of rotation.
__
∆ABC is transformed by a <u> clockwise </u> rotation <u> 90 </u> degrees with a center at the <u> origin </u>.
6x3+49x2+126x+104 (I just simplified it, if it is incorrect I'm sorry I didnt understand what you were asking -,^-)
