Answer
<em>36 is a perfect square</em>
<em>50 is not a perfect square</em>
<em>20 is not a perfect square</em>
<em>2 is not a perfect square</em>
<em></em>
<em>So, the answer is 36</em>
<em></em>
<em>Hope this helps! <3</em>
recall that the radius is the distance from the center of a circle to any point on the circle.
we know the center is at -16,-14, and we know that -8,-8 is a point on the circle, so the distance between both must be the radius.
![\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-16}~,~\stackrel{y_1}{-14})\qquad (\stackrel{x_2}{-8}~,~\stackrel{y_2}{-8})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{radius}{r}=\sqrt{[-8-(-16)]^2+[-8-(-14)]^2} \\\\\\ r=\sqrt{(-8+16)^2+(-8+14)^2}\implies r=\sqrt{8^2+6^2} \\\\\\ r=\sqrt{100}\implies \boxed{r=10} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%0A%5C%5C%5C%5C%0A%28%5Cstackrel%7Bx_1%7D%7B-16%7D~%2C~%5Cstackrel%7By_1%7D%7B-14%7D%29%5Cqquad%0A%28%5Cstackrel%7Bx_2%7D%7B-8%7D~%2C~%5Cstackrel%7By_2%7D%7B-8%7D%29%5Cqquad%20%5Cqquad%0Ad%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Cstackrel%7Bradius%7D%7Br%7D%3D%5Csqrt%7B%5B-8-%28-16%29%5D%5E2%2B%5B-8-%28-14%29%5D%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Ar%3D%5Csqrt%7B%28-8%2B16%29%5E2%2B%28-8%2B14%29%5E2%7D%5Cimplies%20r%3D%5Csqrt%7B8%5E2%2B6%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Ar%3D%5Csqrt%7B100%7D%5Cimplies%20%5Cboxed%7Br%3D10%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D)
![\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-16}{ h},\stackrel{-14}{ k})\qquad \qquad radius=\stackrel{10}{ r} \\\\\\\ [x-(-16)]^2+[y-(-14)]^2=10^2\implies \blacktriangleright (x+16)^2+(y+14)^2=100 \blacktriangleleft](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bequation%20of%20a%20circle%7D%5C%5C%5C%5C%0A%28x-%20h%29%5E2%2B%28y-%20k%29%5E2%3D%20r%5E2%0A%5Cqquad%0Acenter~~%28%5Cstackrel%7B-16%7D%7B%20h%7D%2C%5Cstackrel%7B-14%7D%7B%20k%7D%29%5Cqquad%20%5Cqquad%0Aradius%3D%5Cstackrel%7B10%7D%7B%20r%7D%0A%5C%5C%5C%5C%5C%5C%5C%0A%5Bx-%28-16%29%5D%5E2%2B%5By-%28-14%29%5D%5E2%3D10%5E2%5Cimplies%20%5Cblacktriangleright%20%28x%2B16%29%5E2%2B%28y%2B14%29%5E2%3D100%20%5Cblacktriangleleft)
Answer:
option c)
d = 1
Step-by-step explanation:
Given the equation in the question,
-3d / (d² - 2d - 8) + (3 / d-4) = (-2 / d+2)
quadratic factorisation
-3d / (d+2)(d-4) + (3 / d-4) = (-2 / d+2)
-3d / (d+2)(d-4) = (-2 / d+2) - (3 / d-4)
taking LCM on right side
-3d / (d+2)(d-4) = ( -2(d-4) - 3(d+2)) / (d+2)(d-4)
canceling (d+2)(d-4) on both sides
-3d = -2(d-4) - 3(d+2)
-3d = -2d + 8 - 3d - 6
-3d + 2d + 3d = 8 - 6
2d = 2
d = 1
