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____ [38]
3 years ago
13

Find the area of the trapezoid. Answer options: 60sqrt3, 52sqrt3, 44sqrt3 -24, 44sqrt3

Mathematics
2 answers:
antoniya [11.8K]3 years ago
7 0

Answer:

= 52sqrt3

Step-by-step explanation:

Area of a trapezium is given by the formula;

1/2(a+b)h

Where a and b are the parallel sides and h is the perpendicular height.

a = 15 ft, b= 11 ft and h = 4√3

Therefore;

Area = 1/2 (15+11) 4√3

        = 1/2 × 26 × 4√3

        = 52√3 ft²

sweet [91]3 years ago
4 0

Answer:

Choice b is correct.

Step-by-step explanation:

We have to find the area of trapezoid.

The formula for area of trapezoid is:

A = 1/2 (a+b )h

In the formula a and b are parallel sides and h is perpendicular height.

In the figure, a = 15 ft , b = 11 ft , h = 4√3 ft

Hence,

A = 1/2 (15+11)(4√3)

A = 1/2 (26)(4√3)

A = 52√3 ft² is the area of trapezoid.

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\huge\text{Hey there!}

\huge\textbf{Equation:}

\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\huge\textbf{Solve:}

\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\mathbf{\rightarrow \dfrac{1\times5+1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

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\huge\textbf{Simplify it:}

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\huge\textbf{Multiply \boxed{\bf \dfrac{5}{2}} to both sides:}

\mathbf{\rightarrow \dfrac{5}{2}\times \dfrac{2}{5}x = \dfrac{5}{2}\times \dfrac{9}{10}}

\huge\textbf{Simplify it:}

\mathbf{\rightarrow x = \dfrac{5}{2}\times \dfrac{9}{10}}

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\mathbf{\rightarrow x = \dfrac{9}{4}}

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\huge\textbf{Therefore, your answer should be:}

\huge\boxed{\mathsf{x = }\frak{2 \dfrac{1}{4}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

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muminat
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