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Leno4ka [110]
3 years ago
10

Helpppppp pleaseeee now

Mathematics
2 answers:
iragen [17]3 years ago
8 0
Probably B but I am not sure
nevsk [136]3 years ago
3 0
The answer would be B
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Can someone help me in this question
Masja [62]

Answer:

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Simplify the expression.

15x-17 or 2x-6

Step-by-step explanation:

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2 years ago
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These People! I can’t do this!!! I need YOU!
Marianna [84]
Let’s solve for “a” and “s”.

a = 927 - 45s
a = 792 - 36s

927 - 45s = 792 - 36s
927 - 792 = 45s - 36s
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1 year ago
A circle has a diameter with endpoints at (6, 5) and (8, 5). Write the equation for the circle.
mario62 [17]

Answer:

(x-7)^2+(y-5)^2=1

Step-by-step explanation:

The two things that are required to formulate the equation of the circle is the center coordinate and the radius of the circle!

<u>Center of the circle:</u>

  • The center of the circle always lies at the midpoint of the endpoints of its diameter: Let's call the endpoints A(6,5) and B(8,5).

Using the midpoint formula we'll get:

(x_m, y_m) = \left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

(x_m, y_m) = \left(\dfrac{6+8}{2},\dfrac{5+5}{2}\right)

(x_m, y_m) = (7,5)

This is the center coordinate of our circle.

<u>Radius: </u>

The radius of the circle is the distance from the center of the circle to any of the endpoints of the diameter (A or B)

We can use the distance formula:

r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

r = \sqrt{(x_1-x_m)^2+(y_1-y_m)^2}

r = \sqrt{(6-7)^2+(5-5)^2}

r = \sqrt{1^2}

r = 1

<u>Equation of the circle: </u>

The equation is written as:

(x-a)^2+(y-b)^2=r^2

here, (a,b) are the center points of the circle

in our case this is (a,b)=(x_m,y_m)=(7,5)

and r = 1

(x-7)^2+(y-5)^2=1^2

(x-7)^2+(y-5)^2=1

This is the equation of the circle!

3 0
2 years ago
Solve for in terms of A and w. A=w
arlik [135]

Answer:

Step-by-step explanation:

Given A = w:

w in terms of A is w = A, and

A in terms of w is A = w

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2 years ago
What data type (string, integer, float) you would expect the terminal to return?
vazorg [7]
I’m sorry what subject is this I will still help u
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