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tangare [24]
3 years ago
10

Which numbers are a distance of 6 units from −2 on a number line

Mathematics
2 answers:
Burka [1]3 years ago
6 0

Answer:

-8 and 4 are 6 away from -2

Step-by-step explanation:

------/----------------------------------------/----

-9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7

Firdavs [7]3 years ago
5 0
The answer is 4 and -8
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Jensen recorded the daily average temperature (in degrees Fahrenheit) at his home over two weeks' time. ​His results are shown b
strojnjashka [21]

Answer:25

Step-by-step explanation:

73-48=25

To get your answer take the highest number and subtract it from the lowest number

5 0
2 years ago
Whats the awnser to this question
horsena [70]
The sum of the angles of a triangle is 180º.
We have three angles:
∠yxz=3x+5
∠xzy=180º-(8x-14)
∠xyz=4x

Therefore:
(3x+5º) + [180º-(8x-14º)]+(4x)=180º
3x-8x+4x=180º-5º-14º-180º
-x=-19º
x=19º

∠yxz=3x+5º =3(19º)+5º=62º
∠xzy=180º-(8x-14)=180º-(8(19º)-14)=42º
∠xyz=4x=4(19º)=76º

Answer:  m∠yxz= 62º.
8 0
3 years ago
The recycling bin for the school is in the shape of a rectangular prism. The bin has a length of 16 inches, a width of 14 inches
Romashka [77]

Answer:

3150 inches is the volume

Step-by-step explanation:

i hoped this helped

3 0
3 years ago
Complete parts a through c for the given function.
victus00 [196]

Answer:

a. The critcal points are at

x=0,-5,3

b. Then, x = -5   is a maximum and x=3 is a minimum

c. The absolute minimum is at   x = 3  and the absolute maximum is at  x = -5.

Step-by-step explanation:

(a)

Remember that you need to find the points where

f'(x)=0

Therefore you have to solve this equation.

20x^4  + 40x^3 - 300x^2 = 0

From that equation you can factor out    20x^2  and you would get

20x^2 (  x^2  +2x - 15)  = 0

And from that you would have   20x^2 = 0  , so x = 0.

And you would also have  x^2 +2x-15 = 0.

You can factor that equation as    x^2 +2x -15 = (x+5)(x-3) = 0

Therefore   x=-5 ,   x=3.

So the critcal points are at

x=0,-5,3

b.  

Remember that a function has a maximum at a critical point if the second derivative at that point is negative. Since

f''(x) = 80x^3 + 120x^2 -600x\\f''(-5) = 80(-5)^3 + 120(-5)^2 -600(-5) = -4000 < 0\\\\f''(3) = 80(3)^3 + 120(3)^2 -600(3) = 1440 > 0 \\

Then, x = -5   is a maximum and x=3 is a minimum

c.

The absolute minimum is at   x = 3  and the absolute maximum is at  x = -5.

6 0
3 years ago
Read 2 more answers
What is the y-intercept of the graph of the equation y=4(3^x)?
eimsori [14]

Answer:

The y-intercept is (0, 4).

Step-by-step explanation:

At the y-intercept x = 0 so

y = 4(3^0)

y = 4*1 = 4.

So the y-intercept is (0, 4).

8 0
3 years ago
Read 2 more answers
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