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zmey [24]
3 years ago
8

The volleyball team and the wrestling team at Stamford High School are having a joint car wash today,

Mathematics
1 answer:
Sedbober [7]3 years ago
4 0

Answer:

Money raised by each team = 94 + 11 = <em>$105</em>

Number of cars washed = <em>11</em>

Step-by-step explanation:

Money already present with volleyball team = $50

Money raised by washing each car by volleyball team = $5

Let the number of cars washed = x

Money raised by washing cars = $5x

Money already present with volleyball team = $94

Money raised by washing each car by volleyball team = $1

Money raised by washing cars = $1x = $x

Given that, both the teams have raised same amount of money:

50+5x=94+x\\\Rightarrow 44=4x\\\Rightarrow x=11

Money raised by each team = 94 + 11 = <em>$105</em>

Number of cars washed = <em>11</em>

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Kipish [7]

Answer:

Non-Linear

Step-by-step explanation:

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2 years ago
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a quadratic equation has a discriminant of 12. which could be the equation? a.0 = –x2 8x 2 b.0 = 2x2 6x 3 c.0 = –x2 4x 1 d.0 = 4
Norma-Jean [14]

Answer:

Option b which is 2x^2+6x+3=0

Step-by-step explanation:

We have been given the discriminant 12

We have to choose the equation which will satisfy the given discriminant.

We will consider all the given equation one by one

First we will take option a which is -x^2+8x+2=0

Discriminant from the equation we will find by the formula

D=b^2-4ac

Here, a=-1,b=8 and c=2 on substituting the values we will get

D=8^2-4(-1)(2)=72

Hence, option a is incorrect.

Now, we will consider option b which is 2x^2+6x+3=0

Here, a=2,b=6 and c=3 on substituting the values we get

D=(6)^2-4(2)(3)=12

Hence, option b is correct

Therefore, option b is the required answer.

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3 years ago
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2m=p-q/r solve for r
Oduvanchick [21]

To solve for r, you would start by subtracting p from both sides.

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Multiply everything by r.

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Factor r out of the left side of the equation.

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Divide both sides by (2m - p).

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6 0
3 years ago
Please help me I can’t fail it
Hoochie [10]

Answer:

Step-by-step explanation:

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8 0
3 years ago
For which system of equations is (5, 3) the solution? A. 3x – 2y = 9 3x + 2y = 14 B. x – y = –2 4x – 3y = 11 C. –2x – y = –13 x
Alla [95]
The <u>correct answer</u> is:

D) \left \{ {{2x-y=7} \atop {2x+7y=31}} \right..

Explanation:

We solve each system to find the correct answer.

<u>For A:</u>
\left \{ {{3x-2y=9} \atop {3x+2y=14}} \right.

Since we have the coefficients of both variables the same, we will use <u>elimination </u>to solve this.  

Since the coefficients of y are -2 and 2, we can add the equations to solve, since -2+2=0 and cancels the y variable:
\left \{ {{3x-2y=9} \atop {+(3x+2y=14)}} \right. &#10;\\&#10;\\6x=23

Next we divide both sides by 6:
6x/6 = 23/6
x = 23/6

This is <u>not the x-coordinate</u> of the answer we are looking for, so <u>A is not correct</u>.

<u>For B</u>:
\left \{ {{x-y=-2} \atop {4x-3y=11}} \right.

For this equation, it will be easier to isolate a variable and use <u>substitution</u>, since the coefficient of both x and y in the first equation is 1:
x-y=-2

Add y to both sides:
x-y+y=-2+y
x=-2+y

We now substitute this in place of x in the second equation:
4x-3y=11
4(-2+y)-3y=11

Using the distributive property, we have:
4(-2)+4(y)-3y=11
-8+4y-3y=11

Combining like terms, we have:
-8+y=11

Add 8 to each side:
-8+y+8=11+8
y=19

This is <u>not the y-coordinate</u> of the answer we're looking for, so <u>B is not correct</u>.

<u>For C</u>:
Since the coefficient of x in the second equation is 1, we will use <u>substitution</u> again.

x+2y=-11

To isolate x, subtract 2y from each side:
x+2y-2y=-11-2y
x=-11-2y

Now substitute this in place of x in the first equation:
-2x-y=-13
-2(-11-2y)-y=-13

Using the distributive property, we have:
-2(-11)-2(-2y)-y=-13
22+4y-y=-13

Combining like terms:
22+3y=-13

Subtract 22 from each side:
22+3y-22=-13-22
3y=-35

Divide both sides by 3:
3y/3 = -35/3
y = -35/3

This is <u>not the y-coordinate</u> of the answer we're looking for, so <u>C is not correct</u>.  

<u>For D</u>:
Since the coefficients of x are the same in each equation, we will use <u>elimination</u>.  We have 2x in each equation; to eliminate this, we will subtract, since 2x-2x=0:

\left \{ {{2x-y=7} \atop {-(2x+7y=31)}} \right. &#10;\\&#10;\\-8y=-24

Divide both sides by -8:
-8y/-8 = -24/-8
y=3

The y-coordinate is correct; next we check the x-coordinate  Substitute the value for y into the first equation:
2x-y=7
2x-3=7

Add 3 to each side:
2x-3+3=7+3
2x=10

Divide each side by 2:
2x/2=10/2
x=5

This gives us the x- and y-coordinate we need, so <u>D is the correct answer</u>.
7 0
3 years ago
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