Answer:
4^3x=4^(4x+4)
Step-by-step explanation:
You can eliminate the first 2 options since those don’t make sense already, and the last option changed 64 to 2^6 which is correct, but when they changed the other side. They should have multiplied 8 to both x and 1 which would have made the whole term 2^(8x+8) and not 2^(8x+1). Left with the third option, 4 to the power of 3 is 64 so the left side makes sense, 4^3x=64^x, on the right side, 4^4 equals 256, so the whole exponent should multiply by 4 so from 256^(x+1) you get 4^4(x+1) giving 4^(4x+4) making the third choice the right answer.
Step-by-step explanation:
S+T+U=180°{sum of angle of triangle}
- 68°+90°+U=180°
- U=180-158°
- U=22°
sin theta= p/h
sin22°=x/83
o.37=x/83
x=0.37×83
x=30.71
x=31
stay safe healthy and happy.
11c-4c = 7c
5c+2c= 7c
3c+7c= 10c
11c-4c= 5c+2c =A
Answer:
Blue
Step-by-step explanation:
Blue = 43.5/1.25
34.8 mpg
Red = 21 3/5 / 4/5 = 21.6/0.8
27 mpg
It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if
</span><span>
</span><span>In notation we write respectively
</span>
Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence
Thus these two limits, the one from above and below are equal if and only if
4c + 20 = 16 - c²<span>
Or in other words, the limit as x --> 4 of f(x) exists if and only if
4c + 20 = 16 - c</span>²
That is to say, if c = -2, f(x) is continuous at x = 4.
Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers 
