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3 years ago

What is the answer for both 6 and 8

Mathematics

2 answers:

shepuryov [24]3 years ago

7 0

6 = 19/8 or 2 3/8.

8 = 65/12 or 5 5/12

Your welcome!! \( ^ u ^ )/

garri49 [273]3 years ago

7 0

6=9/18

8= 65/12

Hoped I helped you

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Given the formula a = s2 + 3b - c , find the value of a when s = 7, b = 13 and c = -24.

galben [10]

Answer:

a = 112

Step-by-step explanation:

$a =s^{2} +3b-c$

Given that,

s = 7

b = 13

c = (-24)

Let's solve for a now.

$a =s^{2} +3b-c$

$a = 7^{2} +3*13-(-24)\\$

$a=49+39+24\\$

$a=88+24$

$a=112$

Hope this helps you.

Let me know if you have any other questions :-)

3 0

3 years ago

PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS

Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

$a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\$

With respect to reference angle A, we have:

opposite side = a = 4
adjacent side = b = $\sqrt{33}$
hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

$\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\$

Then cosine which is adjacent over hypotenuse

$\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\$

Tangent is the ratio of opposite over adjacent

$\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\$

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

cosecant, abbreviated as csc, is the reciprocal of sine
secant, abbreviated as sec, is the reciprocal of cosine
cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

$\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{ ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

------------------------------------------------------

Summary:

The missing side is $b = \sqrt{33}$

The 6 trig functions have these results

$\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

7 0

1 year ago

Please help ASAP!!!!

snow_tiger [21]

Answer:

Step-by-step explanation:

1/4πr² + (2x4) - 1/4πr²

r = 4

6 0

3 years ago

Read 2 more answers

Write each number without exponent 6.453 x 10^-3

Solnce55 [7]

Answer:

.006453

Step-by-step explanation:

6.453 x 10^-3

Move the decimal 3 places to the left since the exponent is negative

006.453

.006453

7 0

3 years ago

the perimeter of a rectangular picture frame is 32 in the length of the frame is 2 inches longer than the width what are the dim

stich3 [128]

Answer:

the length is 9 in. and the width is 7 in.

Step-by-step explanation:

this is hard to explain but i promise that this is the correct answer.

7 0

3 years ago