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3 years ago

Please show your work. Thank you for taking the time of day to help me!

Mathematics

2 answers:

34kurt3 years ago

7 0

Answer:

Step-by-step explanation:

Look at the bottom line of the chart.

He sold 41 sides of French fries and 40 sides of onion rings.

41 + 40 = 81

Since he sold a total of 81 sides with bacon cheeseburgers, that means he sold a total of 81 bacon cheeseburgers.

We have a ratio:

81 bacon cheeseburgers to 40 sides of onion rings

Now he sold 120 bacon cheeseburgers, so we set up a proportion to find the number of sides of onion rings. Let the unknown number be x.

81 burgers is to 40 sides as 120 burgers is to x sides

81/40 = 120/x

We solve for x by cross multiplying.

81x = 40 * 120

81x = 4800

x = 4800/81 = 59.3

That means he serves 59 sides of onion rings.

Each serving of onion rings is half pound.

59 * 0.5 = 29.5

For 120 bacon cheeseburgers, he serves approximately 29.5 lb of onion rings.

Answer: 30

Helen [10]3 years ago

6 0

Answer:

30 pounds

Bacon cheeseburger with onion rings:

(41 + 40)

= 0.4938

then,

120 x 0.4938 = 59.256

then,

59.256 x .50 = 29.628

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QUESTION 1

If a function is continuous at $x=a$ , then $\lim_{x \to a}f(x)=f(a)$

Let us find the limit first,

$\lim_{x \to 4} \frac{x-4}{x+5}$

As $x \rightarrow 4$ , $x-4 \rightarrow 0$ , $x+5 \rightarrow 9$ and $f(x) \rightarrow \frac{0}{9}=0$

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$f(4)=\frac{4-4}{4+5} =\frac{0}{9}=0$

Since

$\lim_{x \to 4} f(x)=\frac{x-4}{x+5}=f(4)$ , the function is continuous at $a=4$ .

QUESTION 2

The correct answer is table 2. See attachment.

In this table the values of x approaches zero from both sides.

This can help us determine if the one sided limits are approaching the same value.

As we are getting closer and closer to zero from both sides, the function is approaching 2.

The values are also very close to zero unlike those in table 4.

The correct answer is B

QUESTION 3

We want to evaluate;

$\lim_{x \to 1} \frac{x^3+5x^2+3x-9}{x-1}$

using the properties of limits.

A direct evaluation gives $\frac{1^3+5(1)^2+3(1)-9}{1-1}=\frac{0}{0}$ .

This indeterminate form suggests that, we simplify the function first.

We factor to obtain,

$\lim_{x \to 1} \frac{(x-1)(x+3)^2}{x-1}$

We cancel common factors to get,

$\lim_{x \to 1} (x+3)^2$

$=(1+3)^2=16$

The correct answer is D

QUESTION 4

We can see from the table that as x approaches $-2$ from both sides, the function approaches $-4$

Hence the limit is $-4$ .

See attachment

The correct answer is option A

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3 years ago