The tensile strength of spider silk is about 1150 MPa, which is 1.15 x 10^9 N/m².
<span>So given that the diameter of the spider silk is 0.15 mm or 1.5 x 10^-4 m. The cross sectional area is approximately: </span>
<span>A = πr² = (3.14)(1.5 x 10^-4 / 2)² = 1.767 x 10^-8 m² </span>
<span>So this means that the amount of force we can apply before the the silk thread is broken is: </span>
<span>F = PA = (1.15 x 10^9)(1.767 x 10^-8) = 20.32 N </span>
<span>F = mg, so m = F/g = (20.32)/(9.81) = 2.07 kg!!! </span>
Answer:
![y=2sin[\frac{\pi}{4}(x+3) ]-5](https://tex.z-dn.net/?f=y%3D2sin%5B%5Cfrac%7B%5Cpi%7D%7B4%7D%28x%2B3%29%20%5D-5)
Step-by-step explanation:
The standard form for a sinusoidal function is given by:
y = Asin[B(x - C)] + D
Where A is the amplitude of the sine wave, the period is 2π/B, C is the phase shift and D is the vertical displacement / translation
Given:
A = 2, D = -5 (down), C = -3 (left).
8 = 2π/B; B = π/4
Therefore:
A = 60 but b is unsolvable, plz update question it is wrong
Answer:
21 percent
Step-by-step explanation:
Because 0.21 times 100 gives 21 percent
Answer:
25$
Step-by-step explanation:
