ANSWER
See explanation.
EXPLANATION
Step 1
Graph each of the functions.
and
Step 2
Look for the point of intersection of the two graphs.
From the graph, the two functions intersected at
(0.38,6.14)
XZ ≅ EG and YZ ≅ FG is enough to make triangles to be congruent by HL. Option b is correct.
Two triangles ΔXYZ and ΔEFG, are given with Y and F are right angles.
Condition to be determined that proves triangles to be congruent by HL.
<h3>What is HL of triangle?</h3>
HL implies the hypotenuse and leg pair of the right-angle triangle.
Here, two right-angle triangles ΔXYZ and ΔEFG are congruent by HL only if their hypotenuse and one leg are equal, i.e. XZ ≅ EG and YZ ≅ FG respectively.
Thus, XZ ≅ EG and YZ ≅ FG are enough to make triangles congruent by HL.
Learn more about HL here:
brainly.com/question/3914939
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In ΔXYZ and ΔEFG, angles Y and F are right angles. Which set of congruence criteria would be enough to establish that the two triangles are congruent by HL?
A.
XZ ≅ EG and ∠X ≅ ∠E
B.
XZ ≅ EG and YZ ≅ FG
C.
XZ ≅ FG and ∠X ≅ ∠E
D.
XY ≅ EF and YZ ≅ FG
all three should be zero, bc they're referring to the same thing: "b," (aka the y-intercept).
God loves all of you, remember that ok 777 1000 1699 i
Answer:
Let 3rd digit be x
then 2nd digit = 4x & 1st digit = 4x-2.
It is three digit number. So, there are two case either x=1 or x=2.
Case 1,
3rd digit = 1, 2nd digit = 4 & 1st digit = 4–2=2
Hence number = 241 (ans)
Case 2,
3rd digit = 2 ,2nd digit 8 & 1st digit = 8–2=6.
Hence number = 682 (ans).
Step-by-step explanation: hope this helps :P
