Which shows the given inequalities in slope-intercept form?

Mathematics

1 answer:

yanalaym [24]3 years ago

4 0

Answer: Solve for X

4x−5y<1

Step-by-step explanation:

step 1 add 5y to each side

4x−5y+5y<1+5y

4x<5y+1

Step 2: Divide both sides by 4.

4x4<5y+14

x<54y+14

Answer:

x<54y+14

Let's solve for x.

12y−x<3

Step 1: Add (-1)/2y to both sides.

−x+12y+−12y<3+−12y

−x<−12y+3

Step 2: Divide both sides by -1.

−x−1<−12y+3−1

x>12y−3

Answer:

x>12y−3

now just graph 4x-5y<1 shows the given inequalities in slope -intercep form.

You might be interested in

Determine the sum of the first 9 terms in the geometric series where r= -0.25 and a1= 256.

Damm [24]

$\bf \qquad \qquad \textit{sum of a finite geometric sequence} \\\\ S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ r=\textit{common ratio}\\ ----------\\ r=-0.25\\ a_1=256\\ n=9 \end{cases}$

$\bf S_9=256\left(\cfrac{1-(-0.25)^9}{1-(-0.25)} \right)\implies S_9=256\left( \cfrac{1+0.25^9}{1+0.25} \right) \\\\\\ S_9=256\left( \cfrac{52429}{65536}\right)\implies S_9=\cfrac{52429}{256}\implies S_9=204.80078125$