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3 years ago

14) Simplify: -(16 - 5x) A) 5x - 16 B) 5x + 16 C) -5x - 16 D) - 5x + 16

Mathematics

1 answer:

VLD [36.1K]3 years ago

5 0

Answer: $5x-16$

<u>Switch operations</u>

Before: $-(16 - 5x)$

After: $5x-16$

Before you switch operation you remove the subtraction sign where -(16) is.

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5. f(x) = 3x³ - 4x² +6x and g(x)=5x ³+ 2x²- 3x. What is f(x) - g(x)?

sasho [114]

Answer:

Step-by-step explanation:

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3 years ago

Need help solving pleaseee!!!

natta225 [31]

Answer:

Step-by-step explanation:

50.

line AB that has the points (2,5) and (9,2) hhas the slope

m= (y2-y1) / (x2-x1)= 5-2 / 2-9 = 3/-7 = -3/7

Parallel line have the same slope so m= -3/7 for the line that has the point (-3,4).

Point-slope equation is y-y1 = m (x-x1), y -4 = -3/4 (x+3) or

you can writte it as y= (-3/4)x - 9/4 +16/4 so y = (-3/4)x + 7/4

51.

line PQ has slope m= -6+1 / 4-6 = -5/-2 = 5/2

Perpendicular lines have their slope negative reciprocal of eachother so the line that goes trough the point (1,3) has the slope m= -2/5

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2 years ago

Find the length of diagonal HJ. Round to the nearest hundredth.

Alisiya [41]

Answer:

The length of the diagonal HJ is 10.82 units

Step-by-step explanation:

* Lets revise the rule of the distance between two points

- $d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ , where

$(x_{1},y_{1})$ and $(x_{2},y_{2})$ are the two points

* Lets use this rule to find the length of the diagonal HJ

∵ The coordinates of point H are (-4 , 3)

∵ The coordinates of point J are (5 , -3)

∴ $x_{1}=-4$ and $x_{2}=5$

∴ $y_{1}=3$ and $y_{2}=-3$

- Lets find the length of the diagonal HJ by using the rule above

∴ HJ = $\sqrt{(5-(-4))^{2}+(-3-3)^{2}}=\sqrt{(5+4)^{2}+(-6)^{2}}$

∴ HJ = $\sqrt{(9)^{2}+36}=\sqrt{81+36}=\sqrt{117}=10.81665$

∴ HJ = 10.82

* The length of the diagonal HJ is 10.82 units

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3 years ago

What two fractions make 1/3

Anna11 [10]

1/6 and 1/6 equals 1/3

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3 years ago

If DGH ~ DEF, Find the value of X

DIA [1.3K]

Answer:

$x=25$

Step-by-step explanation:

we know that

DGH ~ DEF ---> given problem

Remember that

If two triangles are similar, then the rtio of its corresponding sides is proportional and its corresponding angles are congruent

$\frac{DG}{DE}=\frac{GH}{EF}$

substitute the given values

$\frac{52}{91}=\frac{x+3}{2x-1}$

$(2x-1)52=(x+3)91\\104x-52=91x+273\\104x-91x=273+52\\13x=325\\x=25$

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3 years ago