I WILL MARK BRAINLIEST IF THIS IS ANSWERED IN LESS THAN 30 MIN.

What is true about the dilation?

IrinaK [193]

Dilation is scale factor, like a dilation scale factor of 2

8 0

2 years ago

Logarithms and exponentials are?

Aneli [31]

Answer:

Logarithms are the "opposite" of exponentials, just as subtraction is the opposite of addition and division is the opposite of multiplication. Logs "undo" exponentials. Technically speaking, logs are the inverses of exponentials. On the left-hand side above is the exponential statement "y = bx

Step-by-step explanation:

3 0

2 years ago

Write the equation of the line that contains the given point and has the given slope.

ArbitrLikvidat [17]

Hey there!!

What is slope-intercept form :

... y = mx + b

( a ) Given :

... ( 2 , -2 ) and slope=1.4

... y = mx + b

... -2 = 2×1.4 + b

... -2 = 2.8 + b

... -4.8 = b

The slope-intercept form :

... y = 1.4x - 4.8

( b ) Given :

... ( -1 , 4 ) and slope = -3.

y = mx + b

... 4 = -3×-1 + b

... 4 = 3 + b

... 1 = b

The slope-intercept form :

... y = -3x + 1

Note :

( m = slope and b = y-intercept )

Hope my answer helps!!

5 0

2 years ago

Read 2 more answers

There are 1920 fence post used in a 12 kilometer stretch of fence how many fence post are used in 1 kilometer of fence

Nonamiya [84]

160 posts are used per 1 km

3 0

3 years ago

If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by

Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by $y = 70t-16t^2$ .

To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

$(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}$

$(\text{Average velocity})_{0.1\ s}=696\ ft/s$

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

$(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}$

$(\text{Average velocity})_{0.01\ s}=7536\ ft/s$

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

$(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}$

$(\text{Average velocity})_{0.001\ s}=75936\ ft/s$

5 0

3 years ago