The answer to the question is 2:3
This depends on how many pages you read all together. I don't fully understand what the question is that you are asking. Could you try to explain it a little bit more? If you can then I could probably help you out :)
Using the normal distribution, it is found that 95.15% of students receive a merit scholarship did not receive enough to cover full tuition.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation for the amounts are given as follows:

The proportion is the <u>p-value of Z when X = 4250</u>, hence:


Z = 1.66
Z = 1.66 has a p-value of 0.9515.
Hence 95.15% of students receive a merit scholarship did not receive enough to cover full tuition.
More can be learned about the normal distribution at brainly.com/question/15181104
#SPJ1
My father taught me a method that I call, 'throwing some thing over the wall'. There is a sample equation for the first picture that shows you how it works. It's a great way to help isolate the variable and I hope that it works for you. The second picture contains the answers I got through the use of this method. I'm sorry for the messy handwriting; I was on a bus.
A. The student added before multiplying.
If they had multiplied 6 and 4 first, the next step would have been too divide. But since they added first, they got 36/24 or 3/2 when the answer should be 13.