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spin [16.1K]
4 years ago
12

What is 2.800830153 rounded to the nearest hundredth

Mathematics
1 answer:
nata0808 [166]4 years ago
3 0

Answer:

2.80

Step-by-step explanation:

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How to simplify this so it equal to c
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Combine terms using exponent rules:
a^m *a^n = a^{m+n} \\  \\ \frac{a^m}{a^n} = a^{m-n}

First rewrite everything so that you have 2^m terms and x^m terms

\frac{2^4 x^4 x^{3/2}}{2^{5/2} x^{5/2}} \\  \\ = 2^{4 - (5/2)} * x^{4 + (3/2)-(5/2)} \\  \\ =2^{(3/2)} x^{(6/2)} \\  \\ = 2 \sqrt{2} x^3
3 0
4 years ago
<img src="https://tex.z-dn.net/?f=%5Cint%5Climits%5E2_1%20%7Bx%5E%7B2%7D-8x%2B8%20%7D%20%5C%2C%20dx" id="TexFormula1" title="\in
12345 [234]

Answer:

{ \underline{ \sf{\int\limits^2_1 {x^{2}-8x+8 } \, dx}  \: =  \:  - 1}}

Step-by-step explanation:

{ \tt{\int\limits^2_1 {x^{2}-8x+8 } \, dx}} \\  \\ =  { \tt{[ \frac{ {x}^{3} }{3}  - 4 {x}^{2}  + 8x ] {}^{2} _{1}}}

Substitute x with the limits:

= { \tt{( \frac{ {2}^{3} }{3}  - 4( {2)}^{2} + 8(2)) - ( \frac{ {1}^{3} }{3}  - 4( {1)}^{2}  + 8(1)) }} \\  = { \tt{( \frac{8}{3}  -  \frac{11}{3} )}} \\  \\  = { \tt{ - 1}}

4 0
3 years ago
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