Seven runners are competing in a race in how many different orders can the runners cross the finish line

Mathematics

2 answers:

kolezko [41]3 years ago

7 0

Answer:

5040

Step-by-step explanation:

hope this helps =)

anastassius [24]3 years ago

6 0

You would multiply 7x6x5x4x3x2x1 to get your answer.

Because there are 7 runners that can get 1st, 6 runners that can get 2nd, 5 runners that can get 3rd, and so on.

7x6x5x4x3x2x1= 5040 different possible combinations.

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Ne4ueva [31]

Answer:

1. $\frac{\sqrt{13} }{3}$

2. 3.2362

3. $\frac{60}{11}$

Step-by-step explanation:

Cot is the trigonometric ratio defined by "adjacent" over "opposite". So, adjacent = 2 and opposite = 3.

By pythagorean theorem, we have the "hypotenuse" as $\sqrt{2^2+3^2}=\sqrt{13}$

Csc is defined as the trig ratio "hypotenuse" over "opposite". We know the sides, so Csc $\theta$ = $\frac{\sqrt{13} }{3}$

First answer choice is right.

By definition, Csc $\theta$ is the inverse of Sine $\theta$ . If given the value of sin theta, to find value of csc theta, we take the reciprocal of it. Hence:

$Csc\theta=\frac{1}{0.3090}\\=3.2362$

Third answer choice is right.

By definition tan and cot are inverse of each other. So the value of tan is the reciprocal of the value of cot. We can simply "flip" the value of tan theta to get the value of cot theta. Hence:

$Cot\theta=\frac{60}{11}$