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3 years ago

What is 3 equivalent ratios for 3:4

2 answers:

6 0

Multiply each part of the ratio by the same number to get an equivalent ratio.
(2)*3 : (2)*4
6:8

(3)*3 : (3)*4
9:12

(4)*3 : (4)*4
12:16

ArbitrLikvidat [17]3 years ago

3 0

A few equivalent ratios for 3:4 are:

6:8
12:16
24:32
60:80
300:400
240:320
45:60
75:100

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Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?

sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have $V=IR^{2}$ and let $H$ be the subset of $V$ of all points on the line

$4x+3y=12$

We need to find if $H$ is a subspace of the vector space $V$ .

In $IR^{2}$ all the possibilities for own subspace of the vector space $IR^{2}$ are :

$IR^{2}$ itself.

The vector $0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]$

All lines in $IR^{2}$ that passes through the origin ( $0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]$ )

We know that $H$ is the subset of $IR^{2}$ of all points on the line $4x+3y=12$

If we look at the equation, the point $\left[\begin{array}{c}0&0\end{array}\right]$ doesn't verify it because :

$4x+3y=12\\4(0)+3(0)=12\\0=12$

Which is an absurd. Therefore, $H$ doesn't contain the origin (and $H$ is a line in $IR^{2}$ ). Finally, it can't be a vector space of $V=IR^{2}$

8 0

3 years ago

How do I solve the linear equation of 27=6(x)+4(y) over 20=2(x)+5(y)

larisa86 [58]

27 = 6x + 4y = 1 7/20 = 3 4/5
20 = 2x + 5y

8 0

3 years ago

How many solutions are in 5x-2-3x(1+2)=2(2+3)

Burka [1]

The Answer Is

X = 3

Hope this Helps

7 0

4 years ago

Read 2 more answers

The joint probability mass function of XX and YY is given by p(1,1)=0p(2,1)=0.1p(3,1)=0.05p(1,2)=0.05p(2,2)=0.3p(3,2)=0.1p(1,3)=

inessss [21]

Answer:

P(Y=1|X=3)=0.125

Step-by-step explanation:

Given :

p(1,1)=0

p(2,1)=0.1

p(3,1)=0.05

p(1,2)=0.05

p(2,2)=0.3

p(3,2)=0.1

p(1,3)=0.05

p(2,3)=0.1

p(3,3)=0.25

Now we are supposed to find the conditional mass function of Y given X=3 : P(Y=1|X=3)

P(X=3) = P(X=3,Y=1)+P(X=3,Y=2) +P(X=3,Y=3)

P(X=3)=p(3,1) +p(3,2) +p(3,3)

P(X=3)=0.05+0.1+0.25=0.4

$P(Y=1|X=3)=\frac{P(X=3,Y=1)}{P(X=3)} =\frac{p(3,1)}{P(X=3)}=\frac{0.05}{0.4}= 0.125$

Hence P(Y=1|X=3)=0.125

8 0

3 years ago

2 other decimal forms of 6.7

NARA [144]

6.70, 6.700, 6.7000, 6.70000, and so on.

5 0

3 years ago

Read 2 more answers