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erastovalidia [21]
4 years ago
7

In 2004, a magazine's circulation was about 1,000,000 readers. In 2014, the magazine had about 2,000,000 readers. Write a linear

model that shows the number of readers, r, of the magazine t years after 2000.
Mathematics
1 answer:
Sever21 [200]4 years ago
8 0

Answer:

m= \frac{r_2 -r_1}{t_2 -t_1}= \frac{2000000-1000000}{14-4}=100000

And then we can use for example the first point (t_1, r_1) = (4, 1000000) to find the intercept:

1000000= 100000*4 + b

b=600000

So then the linear model for this case should be:

r = 100000 t + 600000

Step-by-step explanation:

For this case we want to find a linear model given by:

r =mt+b

Where r = represent the number of readers , t= years after 2000

m = the slope for the model and b the intercept

For this case we can define the following points from the data given:

(t_1, r_1) = (4, 1000000) 4 years after 2000

(t_2, r_2) = (14, 2000000) 14 years after 2000

We can find the slope with the following formula:

m= \frac{r_2 -r_1}{t_2 -t_1}= \frac{2000000-1000000}{14-4}=100000

And then we can use for example the first point (t_1, r_1) = (4, 1000000) to find the intercept:

1000000= 100000*4 + b

b=600000

So then the linear model for this case should be:

r = 100000 t + 600000

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Step-by-step explanation:

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Now B is (-4,5) and A is (2,0)

So AB = \sqrt{(-4-2)^{2} +(5-0)^{2} }  = \sqrt{36 + 25} = \sqrt{61\\} = 7.810...

C is (4,10)

So BC = \sqrt{(-4-4)^{2} +(5-10)^{2} } =\sqrt{64 + 25) } =\sqrt{89} =9.433...

D is (8,7)

So CD = \sqrt{(4-8)^{2} +(10-7)^{2} } =\sqrt{16 + 9} = \sqrt{25} = 5

E is (4,5)

So DE = \sqrt{(8-4)^{2} + (7-5)^{2} }  = \sqrt{16 + 4}  = \sqrt{20}  =  4.472...

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7 0
3 years ago
What multiplied by what other then 2 equals 232
AlekseyPX
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Vinil7 [7]

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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The head of maintenance at XYZ Rent-A-Car believes that the mean number of miles between services is 4639 miles, with a standard
WINSTONCH [101]

Answer:

0.9808 = 98.08% probability that the mean of a sample of 32 cars would differ from the population mean by less than 181 miles

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 4639, \sigma = 437, n = 32, s = \frac{437}{\sqrt{32}} = 77.25

If he is correct, what is the probability that the mean of a sample of 32 cars would differ from the population mean by less than 181 miles?

This is the pvalue of Z when X = 4639 + 181 = 4820 subtracted by the pvalue of Z when X = 4639 - 181 = 4458. So

X = 4820

Z = \frac{X - \mu}{\sigma}

By the Central limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{4820 - 4639}{77.25}

Z = 2.34

Z = 2.34 has a pvalue of 0.9904

X = 4458

Z = \frac{X - \mu}{s}

Z = \frac{4458 - 4639}{77.25}

Z = -2.34

Z = -2.34 has a pvalue of 0.0096

0.9904 - 0.0096 = 0.9808

0.9808 = 98.08% probability that the mean of a sample of 32 cars would differ from the population mean by less than 181 miles

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