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Volgvan
3 years ago
14

A flagpole stands in the middle of a flat, level field. 50 feet away from its base, a surveyor measures the angle to the top of

the flagpole as 48 degrees. How tall is the flagpole? Round to the nearest hundredth of a foot

Mathematics
2 answers:
Lorico [155]3 years ago
6 0

Answer:

54yhqa54u56

Step-by-step explanation:

kirill [66]3 years ago
4 0

Answer:

55.53 feet.

Step-by-step explanation:

We have been given that a flagpole stands in the middle of a flat, level field. 50 feet away from its base, a surveyor measures the angle to the top of the flagpole as 48 degrees.

We can see from attached photo that flagpole, the surveyor forms a right triangle with respect to ground.    

\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}

\text{tan}(48^{\circ})=\frac{h}{50}

\text{tan}(48^{\circ})*50=\frac{h}{50}*50

1.110612514829*50=h

h=1.110612514829*50

h=55.53062574

h\approx 55.53

Therefore, the height of the flagpole is approximately 55.53 feet.

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Answer:

a) s = -16t^{2} + 192t + 96

b) Height of the football after 2 seconds is 448 feet.

ii. The football would not hit the ground after 2 seconds.

Step-by-step explanation:

Given:

s = -16t^{2} + V_{o}t + s_{o}

where: s is the height of the football above the ground, t is the time, V_{o} is the initial velocity and s_{o} is the initial height.

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ii. The football would not hit the ground after 2 seconds.

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timurjin [86]

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