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andrew-mc [135]
3 years ago
12

Find the measurement of d please!

Mathematics
2 answers:
AVprozaik [17]3 years ago
8 0

Answer:

\frac{CD}{FG} = \frac{CE}{FE} \\-> \frac{8}{4} = \frac{10}{d} \\->2 = \frac{10}{d} \\-> d = 5

Naddika [18.5K]3 years ago
3 0

Answer:

Given the information in the diagram, the measurement of <em>d </em> is 5m.

Step-by-step explanation:

In the diagram, we know that the two triangles are similar to each other meaning their segments have equal ratios. We are already given the measurements of two segments. Let's find the ratio.

8 : 4

This can also be written as...

2 : 1

Now, we can find the measurement of <em>d </em>by using this ratio.

\frac{2}{1}* \frac{10}{?}

Cross - multiply.

\frac{10}{2} = 5

So, the measurement of <em>d </em> is 5m.

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The​ quality-control manager at a compact fluorescent light bulb​ (CFL) factory needs to determine whether the mean life of a la
lara31 [8.8K]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 7463

For the alternative hypothesis,

µ ≠ 7463

This is a 2 tailed test

Since the population standard deviation is given, z score would be determined from the normal distribution table. The formula is

z = (x - µ)/(σ/√n)

Where

x = sample mean

µ = population mean

σ = population standard deviation

n = number of samples

From the information given,

µ = 7463 hours

x = 7163 hours

σ = 1080 hours

n = 81

b) z = (7163 - 7463)/(1080/√81) = - 2.5

Looking at the normal distribution table, the probability corresponding to the z score is 0.02

Recall, population mean is 7463

The difference between sample sample mean and population mean is 7463 - 7163 = 300

Since the curve is symmetrical and it is a two tailed test, the x value for the left tail is 7463 - 300 = 7163

the x value for the right tail is 7463 + 300 = 7763

These means are higher and lower than the null mean. Thus, they are evidence in favour of the alternative hypothesis. We will look at the area in both tails. Since it is showing in one tail only, we would double the area. We already got the area below z as 0.02

We would double this area to include the area in the right tail of z = 2.5. Thus

p = 0.02 × 2 = 0.04

It means that in a sample of size 81 light bulbs, we would observe a sample mean of 300 hours or more away from 7463 about 4% of the time by chance alone.

c) Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

The sample mean, x is the point estimate for the population mean.

Margin of error = z × σ/√n

To determine the z score, we subtract the confidence level from 100% to get α

α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025

This is the area in each tail. Since we want the area in the middle, it becomes

1 - 0.025 = 0.975

The z score corresponding to the area on the z table is 1.96. Thus, z score for 95% confidence level is 1.96

Margin of error = 1.96 × 1080/√81

= 235.2

Confidence interval = 7163 ± 23.2

a) Since alpha, 0.05 > than the p value, 0.04, then we would reject the null hypothesis. Therefore, at a 5% level of significance, there is evidence that the mean life is different from 7463 hours

Comparing the results of a and c, it is true that the population mean life is not 7463 hours.

4 0
3 years ago
A nurse is investigating the birth weights of​ non-premature babies. She selects a random sample of 41 such​ babies, and found a
kherson [118]

Answer:

The 95​% confidence interval for the mean birth weight of all ​non-premature babies is between 3350.4 grams and 3662.4 grams. This means that we are 95% sure that true mean birth weight of all non-premature babies is in this interval.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 41 - 1 = 40

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 40 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.0211

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.0211\frac{494.2}{\sqrt{41}} = 156

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 3506.4 - 156 = 3350.4 grams

The upper end of the interval is the sample mean added to M. So it is 3506.4 + 156 = 3662.4 grams

The 95​% confidence interval for the mean birth weight of all ​non-premature babies is between 3350.4 grams and 3662.4 grams. This means that we are 95% sure that true mean birth weight of all non-premature babies is in this interval.

6 0
3 years ago
Homework, 12 points for whoever answers.
adell [148]
The answer to number 1 = 40
5 0
3 years ago
Read 2 more answers
How would you do this???<br> PLEASE EXPLAIN!!!
vladimir1956 [14]
The volume is 180.32 because if u multiply those three numbers u get 180.32. Also, what do u mean by SA
6 0
3 years ago
Are the triangles similar? If yes, write a similarity statement and explain how you know how they are similar. If not, explain.
Triss [41]

Answer:

Please find attached pdf

Step-by-step explanation:

Download pdf
4 0
3 years ago
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