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Sauron [17]
3 years ago
6

Which is equivalent to the expression? x2 + 6x + 4 A) (x + 3)2 + 5 B) (x + 3)2 − 5 C) (x − 3)2 + 5 D) (x − 3)2 − 5

Mathematics
2 answers:
Katena32 [7]3 years ago
6 0

Answer:

Step-by-step explanation:

(x + 3)² − 5   because :

(x + 3)² − 5 = x² +6x+9 -5 =x²+6x+4

Vanyuwa [196]3 years ago
6 0

Answer:

B) (x + 3)^2 - 5

Step-by-step explanation:

the equation is: x^2 + 6x + 4

we have an equation of the form

ax^2+bx+c

where

a=1,b=6,c=4

and we must complete the square to obtain a perfect square binomial,

we must add and substract the following:

(\frac{b}{2a} )^2

which is:

(\frac{6}{2*1} )^2=3^2

and then the equation becomes:

x^2 + 6x + 4+3^2-3^2

where the terms x^2+6x+3^2 are the components of the perfect square binomial: (x+3)^2

and thus, the equation now is:

(x+3)^2+4-3^2\\=(x-3)^2+4-9\\=(x+3)^2-5

the answer is: B) (x + 3)^2 - 5

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40 POINTS AND BRAINLIEST
ladessa [460]

Answer:

120

Step-by-step explanation:

As x goes from 1 to 2, y increases by 4 from 4 to 8

As x goes from 2 to 3, y increases by 4 from 8 to 12

We increase by 4 each time

The formula for an arithmetic sequence is

an = a1+d(n-1)

where a1 is the first term which is 4

d is the common difference or the number we add each time which is 4

n is the term we are looking for which is 30

a30 = 4 +4 (30-1)

a30 = 4+4(29)

       = 4+116

      = 120

5 0
3 years ago
Read 2 more answers
What is the quotient (3x4 + 4x – 15) + (x + 3)?
Hoochie [10]

Answer:

3x-5 and r=0

Step-by-step explanation:

We can do it by long division method  the required quotient is 3x-5 and r=0

not 3x-1 , r=1

multiply the divisor with 3x  we will get to cancel out the first term of dividend

Now after solving we will get  

Now, multiply the divisor by -5 we will get -5x-15 which will cancel the entire dividend.

5 0
3 years ago
An object is acted upon by the forces F1=<10​,6​,4> and F2=<0​,3​,9>. Find the force F3 that must act on the object
murzikaleks [220]

\vec F_3=\langle x,y,z\rangle is a force vector such that

\vec F_1+\vec F_2+\vec F_3=\vec0

\implies\langle10,6,4\rangle+\langle0,3,9\rangle+\langle x,y,z\rangle=\langle0,0,0\rangle

\implies\begin{cases}10+x=0\\9+y=0\\13+z=0\end{cases}\implies x=-10,y=-9,z=-13

So the missing force is

\boxed{\vec F_3=\langle-10,-9,-13\rangle}

8 0
2 years ago
in the xy-plane the graph of y=x^2 and the circle with center (0,1) ad radius 3 have how many points of intersection?
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I think this attachment will help you

7 0
3 years ago
What is 3x - y = 17<br> x + y = -5
Virty [35]

Answer:

{x,y}={6,1}

Step-by-step explanation:

3 0
3 years ago
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