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Sauron [17]
3 years ago
6

Which is equivalent to the expression? x2 + 6x + 4 A) (x + 3)2 + 5 B) (x + 3)2 − 5 C) (x − 3)2 + 5 D) (x − 3)2 − 5

Mathematics
2 answers:
Katena32 [7]3 years ago
6 0

Answer:

Step-by-step explanation:

(x + 3)² − 5   because :

(x + 3)² − 5 = x² +6x+9 -5 =x²+6x+4

Vanyuwa [196]3 years ago
6 0

Answer:

B) (x + 3)^2 - 5

Step-by-step explanation:

the equation is: x^2 + 6x + 4

we have an equation of the form

ax^2+bx+c

where

a=1,b=6,c=4

and we must complete the square to obtain a perfect square binomial,

we must add and substract the following:

(\frac{b}{2a} )^2

which is:

(\frac{6}{2*1} )^2=3^2

and then the equation becomes:

x^2 + 6x + 4+3^2-3^2

where the terms x^2+6x+3^2 are the components of the perfect square binomial: (x+3)^2

and thus, the equation now is:

(x+3)^2+4-3^2\\=(x-3)^2+4-9\\=(x+3)^2-5

the answer is: B) (x + 3)^2 - 5

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Please help thank you! will give brainliest!
VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

  • A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
  • B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
  • C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

brainly.com/question/15161224

#SPJ1

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2 years ago
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