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anzhelika [568]
2 years ago
11

1. How is being able to find the least common

Mathematics
1 answer:
Igoryamba2 years ago
3 0

Step-by-step answer:

For relatively small denominators, the easiest way is to multiply the two denominators AND divide by the highest common factor (HCF).

For example, adding 5/24+3/16

24*16 = 384  

(use a calculator if necessary, for mental calculation, 24*16=20^2-4^2=400-16=384 ).

The highest common factor (HCF) is 8, since 24/8=3, 16/8=2, 3 and 2 do not have any more common factors, so it is the HCF.

The lowest common multiple (LCM) is then 384/8 = 48

For someone good at factoring, we see that the factors are:

24={2^3,3}

16={2^4} = {2^3,2}

so the LCM is either 16*3=48, or 24*2=48.

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Vikentia [17]

Answer:

a)0.25

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Step-by-step explanation:

Possible outcomes when dice are rolled : 1 ,2 ,3,4,5 ,6

Even= 2,4,6  

Odd = 1 ,3 , 5

Probability of getting even =\frac{3}{6}=\frac{1}{2}

Probability of getting odd = \frac{3}{6}=\frac{1}{2}

4 dices are rolled together

a)P(3 even and 1 odd numbers)

P(3 even and 1 odd numbers)=^4C_3 (\frac{1}{2})^3 (\frac{1}{2})^1

P(3 even and 1 odd numbers)=\frac{4!}{3!1!} (\frac{1}{2})^3 (\frac{1}{2})^1 =0.25

b)P(2 even and 2 odd numbers)

P(2 even and 2 odd numbers)=^4C_2 (\frac{1}{2})^2 (\frac{1}{2})^2

P(3 even and 1 odd numbers)=\frac{4!}{2!2!} (\frac{1}{2})^2 (\frac{1}{2})^2=0.375

6 0
2 years ago
The base of a cylindrical candle has an area of
Fudgin [204]

The volume of the cylindrical candle that has a base area of 12.56 inches is 12.56h inches³.

<h3>Volume of of cylinder</h3>

volume of a cylinder = πr²h

where

  • r = radius
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Therefore,

volume of a cylinder = πr²h

Area of the base = πr²

Therefore,

Area of the base = 12.56 inches²

volume of the cylindrical candle = 12.56h inches³

learn more on volume here: brainly.com/question/11459769

#SPJ1

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