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BARSIC [14]
4 years ago
15

I have no idea how to answer this prompt.

Mathematics
1 answer:
Natali5045456 [20]4 years ago
3 0
First,search through all your mathematical vocabulary words. Next rewrite the pattern using words.
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Classify the triangle with the given side lengths: 5, 9, 10
Volgvan
This can be a right triangle
6 0
3 years ago
Write three expressions that are equivalent to 2^6
aleksandr82 [10.1K]

Answer:

well 2^6 = 64 so 8x8, 32x2 and 16x4 would all be correct

4 0
3 years ago
What is the probability that a randomly selected permutation of the letters A, A, C, C, L, L, O, R, T, U would spell "calculator
kirill [66]

Answer:

See explanation

Step-by-step explanation:

Total number of letters = n! = 10

Permutation for 10 letters = n!

                                          = 10!

                                          = 10*9*8*7*6*5*4*3*2*1

                                          = 3628800

From n letters:

Number of A = 2

Number of C = 2

Number of  L = 2

A₁, A₂, C₁, C₂, L₁, L₂, O, R, T, U

Out of 3628800 permutations the word calculator can be spelled as:

C₁ A₁ L₁ C₂ U L₂ A₂ T O R

C₂ A₂ L₂ C₁ U L₁ A₁ T O R

and so on

So total number of different permutations are  

(permutation of number of letters) / permutation of (number of As * number of Cs * number of Ls)

  =  10! / (2! 2! 2 !)  

  = 10*9*8*7*6*5*4*3*2*1 / (2*1) (2*1) (2*1)

  = 3628800 / 2 * 2 * 2

  =  3628800 / 8

  =   453600

Hence probability that a randomly selected permutation of the letters A, A, C, C, L, L, O, R, T, U would spell "calculator" is:

 1 / total number of different permutations  

= 1 / 10! / (2! 2! 2 !)  

= 1/453600

= 0.000002

8 0
3 years ago
The area of square C is 100 square units and the area of square B is 64 square units. What would be the area of square A?
rjkz [21]

Answer: The area of square A is 28 square units because the area is decreasing by 36 and the angles on each side is decreasing by 9

Step-by-step explanation:

100 divide by 4 sides = 25

64 divide by 4 sides = 16

28 divide by 4 sides = 7

7 0
3 years ago
the Hog's head pub decide to make mixture thst is 50% butterbeer. how much of an 80% butterbeer solution should mixed with 20 ga
evablogger [386]
There are 20 gallons of 20% butterbeer solution.
Assume there are x gallons of 80% solution.

So total amount of the solution will be (x+20) gallons
The final solution is 50%.

So, we can set up the equation as:

0.2(20)+0.8(x)=0.5(x+20) \\ \\ 4+0.8x=0.5x+10 \\ \\ 0.8x-0.5x=10-4 \\ \\ 0.3x=6 x=20.

Thus, there will be 20 gallons of 80% butterbeer solution that is needed to be mixed with 20 gallons of 20% butterbeer solution. 

4 0
3 years ago
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