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3 years ago

I have no idea how to answer this prompt.

Mathematics

1 answer:

Natali5045456 [20]3 years ago

3 0

First,search through all your mathematical vocabulary words. Next rewrite the pattern using words.

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What is the surface area of this figure?

jeyben [28]

548 is the correct answer.
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3 years ago

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Please help me with this!

marishachu [46]

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3 years ago

In KLM, LM=7 and angle K=45. Find KL. Leave your answer in simplest radical form.

Sphinxa [80]

Answer in simplest radical form would be 7.(:

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3 years ago

In the circle below, suppose m VUX = 152° and mZUVW = 77º. Find the following.

bezimeni [28]

Given:

In the circle, $m(\overarc{VUX})=152^\circ$ and $m(\angle MUV)=77^\circ$ .

To find:

The following measures:

(a) $m\angle VUX$

(b) $m\angle UXW$

Solution:

According to the central angle theorem, the central angle is always twice of the subtended angle intercepted on the same same arc.

$m(VUX)=2\times m\angle VWX$

$152^\circ=2\times m\angle VWX$

$\dfrac{152^\circ}{2}=m\angle VWX$

$76^\circ=m\angle VWX$

In a cyclic quadrilateral, the opposite angles are supplementary angles.

UVWX is a cyclic quadrilateral. So,

$m\angle VUX+m\angle VWX=180^\circ$ [Opposite angles of a cyclic quadrilateral]

$m\angle VUX+76^\circ=180^\circ$

$m\angle VUX=180^\circ-76^\circ$

$m\angle VUX=104^\circ$

Now,

$m\angle UXW+m\angle UVW=180^\circ$ [Opposite angles of a cyclic quadrilateral]

$m\angle UXW+77^\circ =180^\circ$

$m\angle UXW=180^\circ-77^\circ$

$m\angle UXW=103^\circ$

Therefore, $m\angle VUX=104^\circ$ and $m\angle UXW=103^\circ$ .

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3 years ago

-24 = -3w +21 what is w?

yuradex [85]

Answer:

w=15

Step-by-step explanation:

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3 years ago