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AysviL [449]
3 years ago
12

H(x)=(x+5)^2 if we solve h(x)=36

Mathematics
1 answer:
Ivan3 years ago
6 0

Answer:

x =  - 11

Step-by-step explanation:

Solving

(x + 5)² = 36 ( take square root of both sides )

x + 5 = ± \sqrt{36} = ± 6 ( subtract 5 from both sides )

x = - 5 ± 6

Then

x = - 5 + 6 = 1

x = - 5 - 6 = - 11

The other solution is x = - 11

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Can someone please help me find this answer.
Stels [109]

Answer:

-2x+4

Step-by-step explanation:

multiply all the components of the bracket by - 1.

then you arrive at the answer above

8 0
3 years ago
I dknt undertand nothing
Kitty [74]
Part A :
80x0.18= 14.4


Part B :
80x 0.075= 6


Part C
14.4+6 +80=$100
4 0
3 years ago
What is the value of this expression when a= - 3 and b=-2?<br> (3a^-2b^6/2a^-1b^5)^2
lisabon 2012 [21]

Answer:

so lets just rewrite it with A=-3 amd B=-2

(-9^4^-9^2^5)^2

which is equal to... 1!

Hope This Helps!!!

7 0
3 years ago
What is the constant proportionality for y=2/3x
Lerok [7]
The constant proportionality is 2/3 because it will still be going on
for example- 2/3+2/3= 2/3*2

The number 2/3 goes 
3 0
3 years ago
Read 2 more answers
The reading speed of second grade students in a large city is approximately normal, with a mean of 90 words per
kari74 [83]

Answer:

The probability that a random sample of 10 second grade students from     the city results in a mean  reading rate of more than 96 words per minute

P(x⁻>96) =0.0359

Step-by-step explanation:

<em>Explanation</em>:-

<em>Given sample size 'n' =10</em>

<em>mean of the Population = 90 words per minute</em>

<em>standard deviation of the Population =10 wpm </em>

<em>we will use formula</em>

<em>                            </em>Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }<em></em>

<em>Let X⁻  = 96</em>

                           Z = \frac{96-90 }{\frac{10}{\sqrt{10} } }

                          Z =  1.898

<em>The probability that a random sample of 10 second grade students from     the city results in a mean  reading rate of more than 96 words per minute</em>

<em></em>P(X^{-}>x^{-} ) = P(Z > z^{-} )<em></em>

<em>                    = 1- P( Z ≤z⁻)</em>

<em>                    = 1- P(Z<1.898)</em>

                   = 1-(0.5 +A(1.898)

                   = 0.5 - A(1.898)

                   = 0.5 -0.4641 (From Normal table)

                  = 0.0359

<u><em>Final answer</em></u>:-

The probability that a random sample of 10 second grade students from  

                = 0.0359

4 0
3 years ago
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