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3 years ago

Which is greater 2.48 or 2.83

Mathematics

2 answers:

Artist 52 [7]3 years ago

3 0

Answer:

2.83 is larger by 0.35

Step-by-step explanation:

gayaneshka [121]3 years ago

3 0

Answer:

2.83 because it is a higher number and is closer to the whole number 3

Step-by-step explanation:

hope this helped please mark branliest and rate as it helps!

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2 years ago

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The class sizes of elementary school classes in a public school district are normally distributed with an unknown population mea

weqwewe [10]

Answer: $(17.14,\ 22.86)$

Step-by-step explanation:

The confidence interval estimate for the population mean is given by :-

$\overline{x}\pm ME$ , where $\overline{x}$ is the sample mean and ME is the margin of error.

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3 years ago

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$P(U |D ) = 0.198$

$P(O\ n \ B) = 0.188$

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

5 0

3 years ago

An amount of $21,000 is borrowed for 10 years at 3.25% interest, compounded annually. If the loan is paid in full at the end of

Yanka [14]

The formula for total loan cost is attached.
10 years = 120 payments
MONTHLY Interest = .0325 / 12 = 0.0027083333 

total = 0.0027083333 * 21,000 * 120 / (1-(1.0027083333)-120 
total = 6,825 / (1- 0.7228448406 )
total = 6,825 / 0.2771551594 
total = 24,625.20

4 0

3 years ago