✔️0 < x < 1
X -3 < x < -2
✔️-1 < x < 0
X 2 < x < 3
Here's how you do it: you go to the graph, and go to the area where the function connects with 0, and follow it to the path where it connects with 1. Is that specific line decreasing or increasing? Nevermind what happens to it after/before those specific numbers, you're focusing on whether the function is increasing or decreasing from 0 to 1. The same apply to the other 3.
The answer is negative 1. This is because the sequence follows a pattern of the final number being 4, then 9, then 4 again. near the end of the sequence, you will end at the term of positive 4, which when 5 is subtracted from it (the pattern is -5), the first negative term is -1.
P = 2(l + w)
w = l/2
Plug in 'l/2' for 'w' in the equation with '66':
66 = 2(l + l/2)
66 = 2l + 2l/2
66 = 2l + l
66 = 3l
22 = l
So the length is 22.
Now plug this in to find the width.
66 = 2(22 + w)
66 = 44 + 2w
22 = 2w
11 = w
So the width is 11, and the length is 22.
Answer:
c^(8)
Step-by-step explanation:
(c^5)(c)(c^2)
When the bases are the same, we can add the exponents when multiplying
The implied exponent on c is c^1
c^( 5+1+2)
c^(8)
Draw a cartesian plane, create a graph with the equation x = y^2 - 2
then substitute numbers into the equation so that it is true, to find points on the graph, e.g. substitute y with 1, you get
x = 1^2 - 2
x = 1 - 2 = -1, so when y = 1, x = -1, this point is (-1, 1)
for the next substitute y with 2,
x = 2^2 - 2
x = 4 - 2 = 2, the point is (2, 2)
you might want to try negative values of y
y = -1, x = (-1)^2 - 2
x = -1 the point is (-1,-1)
then plot the points on the graph