One of the roots of the equation 3x^2+7x−q=0 is −5. Find the other root and q.
1 answer:
Answer:
see explanation
Step-by-step explanation:
Since x = - 5 is a root of the equation then substituting x = - 5 into the equation allows q to be found
3(- 5)² + 7(- 5) - q = 0
75 - 35 - q = 0
40 - q = 0 ( subtract 40 from both sides )
- q = - 40 ⇒ q = 40
The equation can now be written as
3x² + 7x - 40 = 0
Factorise to find the other root
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term
product = 3 × - 40 = - 120 and sum = + 7
The factors are + 15 and - 8
Express the x- term using these factors
3x² + 15x - 8x - 40 = 0 ( factor the first/second and third/fourth terms )
3x(x + 5) - 8(x + 5) = 0 ← factor out (x + 5)
(x + 5)(3x - 8) = 0
Equate each factor to zero and solve for x
x + 5 = 0 ⇒ x = - 5 ← root already known
3x - 8 = 0 ⇒ x = ← the other root
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Answer:
We conclude that:
∠A = ∠ FEC
Step-by-step explanation:
Given
△ABD ≅ △EFC
To determine:
∠A =
As
△ABD ≅ △EFC
So the triangles △ABD and △EFC are congruent to each other.
- We know that congruent triangles have equal corresponding parts.
Please check the attached graph.
From the graph, it is clear that ∠A is correspondent to ∠E.
∠A = ∠E
From the attached figure, it is clear that:
∠F can also be denoted by ∠ FEC
as
∠A = ∠E
so
∠A = ∠ FEC
Therefore, we conclude that:
∠A = ∠ FEC
