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cricket20 [7]
3 years ago
7

Find the Vertex Point.

Mathematics
1 answer:
horrorfan [7]3 years ago
6 0
The vertex point would be (1,3)


explanation:
-b/2a:
-(-2)/2(1)
2/2=1
Plug 1 in for all the X’s
y=1^2-2(1)+4
y=3
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7/8 × 16. Use a model to solve.
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3 years ago
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Complete the equation of the line through ( − 8 , 8 ) (−8,8) and ( 1 , − 1 0 ) (1,−10). Use exact numbers.
yan [13]

\bf (\stackrel{x_1}{-8}~,~\stackrel{y_1}{8})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{-10}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-10-8}{1-(-8)}\implies \cfrac{-18}{1+8}\implies \cfrac{-18}{9}\implies -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-8=-2[x-(-8)] \implies y-8=-2(x+8) \\\\\\ y-8=-2x-16\implies y=-2x-8

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Un hipopótamo pesa 1.5 montones.Cuanto pesa en onzas
S_A_V [24]

Answer: 24

Step-by-step explanation:

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3 years ago
I need help solving this difficult math problem step by step to get the answer. <br> -10+-30/10 x 3
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Answer:

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2 years ago
A small business makes cookies and sells them at the farmer's market. The fixed monthly cost for use of a Health Department–appr
DENIUS [597]

Answer:

Cost function:

C(x)=790+2.88x

Revenue function

R(x)=6x

Profit function

P(x)=3.12x-790

Dozens needed for a specific profit P

x=\dfrac{P-790}{3.12}

If 150 dozen cookies are sold the profit is negative, so the business is loosing $322.

Step-by-step explanation:

We can list the costs as:

- Fixed monthly cost, $790/month.

- Variable costs, $0.24/cookie, which are (12*0.24) = $2.88 a dozen.

Then, we can write the cost function C(x) as:

C(x)=790+2.88x

being C(x): the monthly cost and x: the number of dozens produced per month.

The revenue can be calculated as the price ($6 a dozen) multiplied by the number of dozens x:

R(x)=6x

The profit can be calculated substracting the total cost C(x) from the revenue R(x).

P(x)=R(x)-C(x)\\\\P(x)=(6x)-(790+2.88x)=(6-2.88)x-790\\\\P(x)=3.12x-790

The number of cookies (in dozens) that must be produced and sold for a monthly profit can be calculated from the previous equation for P(x).

For a monthly profit P, the number of dozens that need to be sold are:

P=3.12x-790\\\\P+790=3.12x\\\\\\x=\dfrac{P-790}{3.12}

If 150 dozen cookies are sold, the profit made is:

P(150)=3.12(150)-790=468-790=-322

The profit is negative, so the business is loosing $322.

6 0
3 years ago
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