Answer:
Step-by-step explanation:
A vector quantity is represented by
where y = y-coordinate and x = x-coordinate
Since vector AB represents a vector in 3rd quadrant,
It starts from point A and ends at B,
Therefore, coordinates of B are (-9, -4)
=
Similarly vector CD starts with C and ends at D in the 2nd quadrant,
Therefore coordinates of D will be (-5, 4)
The measure of angle E will be 90 degrees as well.
Assume EFG = JKL.
If mLJ = 90°, mL K = 26°, and m< L = 64°,
<h3>What is the congruent triangle?</h3>Two triangles are said to be congruent if the length of the sides is equal, a measure of the angles are equal and they can be superimposed.
We have been given an image of two congruent triangles.
Since, EFG = JKL
therefore, the corresponding angles will be congruent.
m < J = 90° = m< E = 90
By congruence measure of angle, J will be equal to the measure of angle E.
Hence, The measure of angle E will be 90 degrees as well.
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Answer:
The 90% confidence interval for the mean test score is between 77.29 and 85.71.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 25 - 1 = 24
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.064
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29
The upper end of the interval is the sample mean added to M. So it is 81.5 + 4.21 = 85.71.
The 90% confidence interval for the mean test score is between 77.29 and 85.71.