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pashok25 [27]
2 years ago
13

It is known that a polynomial has solution if -1 and 3i. What is the lowest possible degree polynomial with these solutions? (1)

1 (2) 2 (3) 3 (4) 4
Mathematics
1 answer:
agasfer [191]2 years ago
4 0

Answer:

(3) the polynomial has degree 3. If it were a complex coefficient polynomial, then the answer is 2.

Step-by-step explanation:

I am assuming it is a real coefficient polynomial, otherwise the answer will be 2. Since 3i is a root, then so is its conjugate -3i, therefore the polynomial is a multiple of (x-(-1)) *(x-3i) * (x-(-3i)) = (x+1) * (x²+9), which has real coefficients. Hence, its degree is atleast 3. Option (3) is correct

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ANSWER

The set of the intersection  of {2,3,5,7} and {2,5,11,13} is

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EXPLANATION


Let A={2,3,5,7}


and


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The elements that are common to both sets are 2 and 5. So, we write;

A \cap B={2,5}


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