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pashok25 [27]
3 years ago
13

It is known that a polynomial has solution if -1 and 3i. What is the lowest possible degree polynomial with these solutions? (1)

1 (2) 2 (3) 3 (4) 4
Mathematics
1 answer:
agasfer [191]3 years ago
4 0

Answer:

(3) the polynomial has degree 3. If it were a complex coefficient polynomial, then the answer is 2.

Step-by-step explanation:

I am assuming it is a real coefficient polynomial, otherwise the answer will be 2. Since 3i is a root, then so is its conjugate -3i, therefore the polynomial is a multiple of (x-(-1)) *(x-3i) * (x-(-3i)) = (x+1) * (x²+9), which has real coefficients. Hence, its degree is atleast 3. Option (3) is correct

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Natali [406]

a. Solve for x

Since  angle MLN and angle JKL are complementary, the value of x = 8

Since  angle MLN and angle JKL are complementary, their sum equal 90°.

Since  angle MLN = 7x - 1 and angle JKL = 4x + 3, we have that

7x - 1 + 4x + 3 = 90

Collecting like terms, we have

7x + 4x - 1 + 3 = 90

Simplifying, we have

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b. Find m angle MLN and m angle JKL .

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angle MLN = 7x - 1

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So, Since angle MLN=7x-1 and angle JLK=4x+3  thus, angle MLN = 55° and angle JKL = 35°

Learn more about complementary angles:

brainly.com/question/13389583

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