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pashok25 [27]
2 years ago
13

It is known that a polynomial has solution if -1 and 3i. What is the lowest possible degree polynomial with these solutions? (1)

1 (2) 2 (3) 3 (4) 4
Mathematics
1 answer:
agasfer [191]2 years ago
4 0

Answer:

(3) the polynomial has degree 3. If it were a complex coefficient polynomial, then the answer is 2.

Step-by-step explanation:

I am assuming it is a real coefficient polynomial, otherwise the answer will be 2. Since 3i is a root, then so is its conjugate -3i, therefore the polynomial is a multiple of (x-(-1)) *(x-3i) * (x-(-3i)) = (x+1) * (x²+9), which has real coefficients. Hence, its degree is atleast 3. Option (3) is correct

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<u>Q</u><u>uest</u><u>ion</u><u>:</u>

To Simplify:

118 {121÷(11×11)-(-4)-(3-7)}

<u>Solu</u><u>tion</u>:

↠118 {121÷121+4-(-4)}

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↠118{9}

↠118×9

↠1062

▬▬▬▬▬▬▬▬▬▬▬▬

The upper Solution is done by applying BODMAS

<u>Abou</u><u>t</u><u> </u><u>BODMAS</u><u>:</u>

B→ Bracket

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5 0
2 years ago
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VikaD [51]

Answer:

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Step-by-step explanation:

7 0
3 years ago
Please solve this simultaneous equation, i'm not that good at it.<br><br> 2r-s=10<br> rs-s^2=12
o-na [289]

Answer:

s = 6, r = 8 or s = 4, r = 7

Step-by-step explanation:

2r - s = 10

2r = 10 + s

r = 5 + s/2 --(1)

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sub (1) into (2):

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therefore s = 6 or s = 4

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7 0
2 years ago
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mr_godi [17]

See the attached figure.

m ∠KAJ = 170° &  m ∠LAM = 80°

We should know that :

m ∠KAJ + m ∠LAM + m ∠KAL + m ∠MAJ = 360°

∴ m ∠KAL + m ∠MAJ = 360° - (m ∠KAJ + m ∠LAM)

∴ m ∠KAL + m ∠MAJ = 360° - (170°+80°) = 360° - 250° = 110°

But : m ∠KAL = m ∠MAJ ⇒⇒⇒ <u>Opposite angles.</u>

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∴ m ∠MAJ = 110° ÷ 2 = 55°


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Ede4ka [16]

Answer:

You have to have the graph to answer it.

Step-by-step explanation:

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