Josh got to school at half past 8

Mathematics

1 answer:

rodikova [14]2 years ago

6 0

Kay. What about it?? What about Josh and him getting to school at half past eight??

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Does anybody like anime ??

ad-work [718]

Of course bro why wouldn’t we like anime

3 0

3 years ago

Please please help me!!

Alona [7]

Answer:

g(x) = f(x+1) + 1

Step-by-step explanation:

Since the graph is only moved you don't have to worry about the slope.

To move the graph to the left you add to the x and in this case, it only moved 1 over.

to move the graph up you add to the whole function and in this case, it only moved up 1.

4 0

3 years ago

How to show these 2 problems are inverses

nataly862011 [7]

$\bf \begin{cases}
f(x)=\sqrt[3]{7x-2}\\\\
g(x)=\cfrac{x^3+2}{7}
\end{cases}\\\\
-----------------------------\\\\
now
\\\\
f[\ g(x)\ ]\implies f\left[ \frac{x^3+2}{7} \right]\implies \sqrt[3]{7\left[ \frac{x^3+2}{7} \right]-2}\implies \sqrt[3]{x^3+2-2}
\\\\\\
\sqrt[3]{x^3}\implies x\\\\
-----------------------------\\\\
or
\\\\
g[\ f(x)\ ]\implies g\left[\sqrt[3]{7x-2}\right]\implies \cfrac{\left[\sqrt[3]{7x-2}\right]^3+2}{7}
\\\\\\
\cfrac{7x-2+2}{7}\implies \cfrac{7x}{7}\implies x$

thus f[ g(x) ] = x indeed, or g[ f(x) ] =x, thus they're indeed inverse of each other

8 0

2 years ago

Pls answer the question and show how or why

postnew [5]

Answer:

there is no question my dude

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Please help meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Alex_Xolod [135]

Answer:

Step-by-step explanation:

4y+3x

5 0

3 years ago