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4 years ago

Which is the intersection of the sets {2,3,5,7} and {2,5,11,13}?

Mathematics

1 answer:

pishuonlain [190]4 years ago

4 0

ANSWER

The set of the intersection of { $2,3,5,7$ } and { $2,5,11,13$ } is

{ $2,5$ }

EXPLANATION

Let $A=$ { $2,3,5,7$ }

and

$B=$ { $2,5,11,13$ }.

The intersection of the two sets are the elements that are in both set A and set B.

The elements that are common to both sets are 2 and 5. So, we write;

$A \cap B=$ { $2,5$ }

Therefore the correct answer is C

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True or False: Segment Y M is congruent to segment PW. GT Y BM PD W -10 -5 0 5 10 Select one: O True O False

Sauron [17]

Answer:

$\huge\boxed{\mathrm{False}}$

Step-by-step explanation:

Length of YM = 1 - (-6) [This is it's endpoints]

YM = 1 + 7

YM = 8

Length of PW = 9 - 5 [Subtraction of endpoints to get the length]

PW = 4

So, Segment YM is not congruent to segment PW.

7 0

3 years ago

Determine the miles traveled in 5 hours at a rate of 189 miles in 3 hours

Salsk061 [2.6K]

Hey there,

Question : Determine the miles traveled in 5 hours at a rate of 189 miles in 3 hours

Answer :
3 hours = 189 miles
1 hour = 189 miles / 3 hours
= 63 miles
5 hours = 63 miles x 5 hours
= 315 miles

Hope this helps :))

~Top♥

8 0

3 years ago

A closed cylindrical vessel contains a fluid at a 5MPa pressure. The cylinder, which has an outside diameter of 2500mm and a wal

Julli [10]

Answer:

1) Increase in the diameter equals 3.5 mm

2) Increase in the length equals $0.0003724L_{i}$ where $L_{i}$ is the initial length of the vessel.

Step-by-step explanation:

The diametric strain in the vessel is given by

$\epsilon_{D} =\epsilon_{diam}-\nu \epsilon _{axial}$

We have

$\epsilon _{diam}=\frac{\sigma _{hoop}}{E}\\\\\sigma _{hoop}=\frac{\Delta P\times D}{2t}\\\\\therefore \epsilon _{diam}=\frac{\Delta P\times D}{2t\times E}$

Applying values we get

$\therefore \epsilon _{diam}=\frac{5\times 10^{6}\times 2.5}{2\times 20\times 10^{-3}\times 193\times 10^{9}}\\\\\therefore \epsilon _{diam}=\frac{5}{3088}$

Similarly axial strain is given by

$\epsilon _{diam}=\frac{\sigma _{axial}}{E}$

$\sigma _{axial}=\frac{\Delta P\times D}{4t}\\\\\therefore \epsilon _{axial}=\frac{\Delta P\times D}{4t\times E}$

Applying values we get

$\therefore \epsilon _{axial}=\frac{5\times 10^{6}\times 2.5}{4\times 20\times 10^{-3}\times 193\times 10^{9}}\\\\\therefore \epsilon _{diam}=\frac{2.5}{3088}$