The frustum can be considered as consisting of a square pyramid, less the
cut volume.
- The mass of the stand, is approximately 18.60905 kg
Reasons:
The given parameter of the frustum are;
The density of the frustum, ρ = 85 g/cm³
Height of pyramid, h = 9 cm
Side length of base = 10 cm
Height of frustum
By proportional shapes, the side length of the top of the frustum can be found as follows;



B₁ = 10², B₂ = 
Therefore;

The volume of the stand, V ≈ 218.93 cm³
Mass = Volume × Density
∴ Mass of the stand, m = 218.93 cm³ × 85 g/cm³ = 18,609.05 grams = 18.60905 kg.
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Answer:
The answer is = 112
Step-by-step explanation:
3x4 = 12
12 - 2 = 10
10 x 9 = 90 .,. when there is a ) next to a number you multiply
90 + 22 = 112
Answer:
Sometimes
Step-by-step explanation:
Examples:
-5 + 10 = 5 FALSE
-10 + 5 = -5 TRUE
(a.) is the answr. ............................................
#1:Proportional Medians Theorem
#2:BD/FH = CB/GF
#3: 24/16 27/x
So the first ratio is 3/2 because both are divisible by 8. the ratio stays 3/2. 3*9=27. so 2*9=18
x=18
#4: x = 8.5
#5: x = 68
Hope this helps!!